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CCNA Practice Test.

275 free practice questions with answers and explanations.

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Verified against the official content outline

These are original study questions written from published exam objectives—not recalled, copied, or confidential live-exam items. Always confirm current coverage with the official sources linked on this page.

Exam format and study resources

The CCNA is administered by Cisco, with a 2 hours time limit.

This free CCNA practice test has 275 original questions written to Cisco's official content outline, last checked against it on August 6, 2026, 200 of them listed on this page and the rest loaded by the drill. Every question shows a worked explanation, and nothing here requires a signup.

As of 2026, the CCNA exam fee is $300.

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QUESTION 1 / 200Network FundamentalsMedium0/0
An engineer subnets 192.168.10.0/24 into networks that each support at least 30 hosts. Which subnet mask satisfies this requirement while wasting the fewest addresses?
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  1. 1. An engineer subnets 192.168.10.0/24 into networks that each support at least 30 hosts. Which subnet mask satisfies this requirement while wasting the fewest addresses?

    • A. 255.255.255.192 (/26)
    • B. 255.255.255.224 (/27)
    • C. 255.255.255.240 (/28)
    • D. 255.255.255.128 (/25)
    Show answer & explanation

    Answer: B
    A /27 mask leaves 5 host bits (2^5-2=30 usable hosts), exactly meeting the requirement with minimal waste. A /28 gives only 14 usable hosts (too few), while /26 and /25 provide far more addresses per subnet than needed, wasting IP space.

  2. 2. Which statement correctly differentiates a Layer 2 switch's collision domain behavior from that of a legacy Ethernet hub?

    • A. A switch places every port in its own collision domain, while a hub shares one collision domain across all ports
    • B. A hub places every port in its own collision domain, while a switch shares one collision domain
    • C. Both switches and hubs place every port in the same broadcast domain and same collision domain
    • D. Switches and hubs both eliminate collision domains entirely by default
    Show answer & explanation

    Answer: A
    Switches forward frames based on MAC address tables and provide dedicated bandwidth per port, so each switch port is its own collision domain; a hub is a physical-layer repeater where all ports share one collision domain. Options B-D reverse or misstate this fundamental distinction.

  3. 3. A network engineer needs a Layer 3 device to fragment a 1500-byte frame that must traverse a link with a smaller MTU. What is the most likely consequence if the Don't Fragment (DF) bit is set in the IP header?

    • A. The router fragments the packet anyway and reassembles it at the far end
    • B. The router drops the packet and may send an ICMP 'fragmentation needed' message back to the sender
    • C. The switch converts the packet to a jumbo frame automatically
    • D. The packet is forwarded unchanged regardless of MTU
    Show answer & explanation

    Answer: B
    When DF is set and the outgoing interface MTU is smaller than the packet, the router cannot fragment it and instead drops the packet, typically returning ICMP type 3 code 4 (fragmentation needed) so the sender can perform Path MTU Discovery. Fragmentation despite DF, silent forwarding, or switch-level frame conversion are not valid IP-layer behaviors.

  4. 4. Which OSI layer is primarily responsible for establishing, managing, and terminating logical connections such as TCP sessions between two hosts?

    • A. Layer 2 (Data Link)
    • B. Layer 7 (Application)
    • C. Layer 4 (Transport)
    • D. Layer 3 (Network)
    Show answer & explanation

    Answer: C
    Layer 4 (Transport) handles end-to-end connection establishment, flow control, and reliability via protocols like TCP; Layer 2 handles framing on a single link, Layer 3 handles logical addressing and routing, and Layer 7 handles application-specific services, none of which manage session-level connection state.

  5. 5. An administrator observes that IPv6 address fe80::1a2b:3c4d:5e6f:7a8b is assigned to a router interface. What is the correct classification and purpose of this address?

    • A. A global unicast address used for internet-routable communication
    • B. A link-local address used only for communication on the local network segment
    • C. A multicast address used to reach all routers on the segment
    • D. A unique local address used for site-local routing across the WAN
    Show answer & explanation

    Answer: B
    Addresses beginning with fe80::/10 are link-local, automatically assigned to every IPv6 interface and used only for on-link communication (e.g., neighbor discovery), never routed off the local segment. Global unicast addresses use 2000::/3, multicast uses ff00::/8, and unique local addresses use fc00::/7.

  6. 6. A switch port configured as an access port receives a frame tagged with 802.1Q VLAN ID 20, but the port is assigned to VLAN 10. What does the switch do with this frame?

    • A. It forwards the frame normally into VLAN 20
    • B. It drops the frame because access ports do not expect or accept tagged frames
    • C. It re-tags the frame with VLAN 10 and forwards it
    • D. It floods the frame to all VLANs as an unknown unicast
    Show answer & explanation

    Answer: B
    Access ports are configured for a single untagged VLAN and do not process 802.1Q tags; a tagged frame arriving on an access port is discarded because it does not match the expected untagged format. The switch does not silently accept, re-tag, or flood such frames across VLANs.

  7. 7. Which EtherChannel negotiation protocol is Cisco proprietary, as opposed to the open-standard alternative?

    • A. LACP (Link Aggregation Control Protocol)
    • B. VTP (VLAN Trunking Protocol)
    • C. PAgP (Port Aggregation Protocol)
    • D. STP (Spanning Tree Protocol)
    Show answer & explanation

    Answer: C
    PAgP is a Cisco-proprietary protocol for negotiating EtherChannel bundles, whereas LACP (IEEE 802.3ad) is the open standard supported across vendors. STP prevents loops and is unrelated to channel negotiation, and VTP synchronizes VLAN databases, also unrelated to link aggregation negotiation.

  8. 8. In Rapid PVST+, a switch port that is neither the root port nor a designated port, but is blocking to prevent a loop, is in which port state and role?

    • A. Forwarding, Root port
    • B. Discarding, Alternate port
    • C. Learning, Designated port
    • D. Forwarding, Backup port
    Show answer & explanation

    Answer: B
    In Rapid PVST+, a port that receives a superior BPDU but is not selected as the root or designated port becomes an alternate port in the discarding state, providing a standby path without forwarding traffic. Root and designated ports forward traffic once stable, so the other options misassign both the state and role.

  9. 9. A wireless engineer is deploying an 802.11 network where multiple lightweight access points must be centrally managed for configuration, RF optimization, and roaming. What component provides this centralized control?

    • A. A wireless LAN controller (WLC)
    • B. An autonomous access point
    • C. A Layer 2 switch acting as a root bridge
    • D. A DHCP relay agent
    Show answer & explanation

    Answer: A
    A wireless LAN controller centrally manages lightweight APs using CAPWAP, handling configuration push, RF management, and client roaming across the AP fleet. Autonomous APs manage themselves independently rather than centrally, and switches or DHCP relays play no role in WLAN-specific control functions.

  10. 10. Two switches connect via a trunk link but have mismatched native VLANs configured on each end. What is the most likely operational impact?

    • A. The trunk fails to come up entirely
    • B. Traffic for the native VLANs may leak between the mismatched VLANs, and CDP/STP may log a native VLAN mismatch warning
    • C. Only voice VLAN traffic is affected, all data VLANs are unaffected
    • D. The switches automatically renegotiate a matching native VLAN via DTP
    Show answer & explanation

    Answer: B
    A native VLAN mismatch causes untagged frames from one native VLAN to be interpreted as belonging to the other switch's native VLAN, potentially leaking traffic between VLANs; Cisco switches typically detect this via CDP and log warnings, and STP may also flag it. The trunk link itself typically stays up, DTP negotiates trunking mode not native VLAN matching, and the issue is not limited to voice VLANs.

  11. 11. Which statement about the differences between static routing and dynamic routing protocols is accurate?

    • A. Static routes automatically adjust when a link fails, while dynamic routes require manual reconfiguration
    • B. Dynamic routing protocols consume more router CPU and bandwidth for updates, but adapt automatically to topology changes
    • C. Static routes cannot be assigned an administrative distance
    • D. Dynamic routing protocols are only usable in single-router networks
    Show answer & explanation

    Answer: B
    Dynamic routing protocols like OSPF or EIGRP exchange periodic or triggered updates, consuming CPU and bandwidth, but automatically reconverge after topology changes; static routes require manual updates but have no such overhead. Static routes do have a default administrative distance (typically 1), and dynamic protocols are designed for multi-router networks, not restricted to single routers.

  12. 12. A router has the following routes to reach 10.0.0.0/24: a static route with administrative distance 1, and an OSPF route with administrative distance 110. Both are in the routing table. Which route is installed and used for forwarding?

    • A. The OSPF route, because OSPF is a link-state protocol
    • B. The static route, because it has the lower administrative distance
    • C. Both routes are installed and traffic is load-balanced
    • D. Neither route is installed; the router uses only directly connected routes
    Show answer & explanation

    Answer: B
    When two routing sources learn the same destination, the router prefers the route with the lowest administrative distance, and a static route's default AD of 1 is lower than OSPF's default AD of 110, so the static route wins. Load-balancing across differing AD routes to the same prefix does not occur, and connected routes are irrelevant here since neither route is directly connected.

  13. 13. An OSPF network has two routers on the same multi-access segment, both configured with the same OSPF priority and no manual DR configuration. What determines which router becomes the Designated Router?

    • A. The router that boots up second
    • B. The router with the fewest interfaces
    • C. The router with the lowest OSPF process ID
    • D. The router with the highest router ID
    Show answer & explanation

    Answer: D
    When OSPF priorities are tied, the router with the highest router ID (derived from a configured loopback, or the highest active IP address if none is set) is elected DR. Process ID is locally significant and not used in DR election, boot order alone doesn't decide the election outcome once priorities tie, and interface count plays no role.

  14. 14. A host with IP 172.16.5.10/22 needs to determine whether 172.16.7.50 is on its local subnet or requires routing through a gateway. What is the correct subnet range for 172.16.5.10/22?

    • A. 172.16.4.0 - 172.16.7.255
    • B. 172.16.5.0 - 172.16.5.255
    • C. 172.16.0.0 - 172.16.255.255
    • D. 172.16.4.0 - 172.16.4.255
    Show answer & explanation

    Answer: A
    A /22 mask (255.255.252.0) creates blocks of 4 in the third octet; 172.16.5.10 falls in the block 172.16.4.0-172.16.7.255, so 172.16.7.50 is within the same subnet and reachable locally without routing. The other ranges reflect /24 or /16 boundaries, which do not match the /22 prefix.

  15. 15. Which routing protocol characteristic best distinguishes EIGRP as an advanced distance-vector protocol from a pure distance-vector protocol like RIP?

    • A. EIGRP uses the Diffusing Update Algorithm (DUAL) to maintain backup routes and converge rapidly without full periodic broadcasts
    • B. EIGRP requires manual configuration of every route with no automatic neighbor discovery
    • C. EIGRP only supports a hop count metric identical to RIP
    • D. EIGRP floods full link-state databases to every router in the area
    Show answer & explanation

    Answer: A
    EIGRP's DUAL algorithm computes feasible successors as backup routes and enables fast, loop-free convergence, and it sends only partial/triggered updates rather than RIP's periodic full-table broadcasts. Flooding full link-state databases describes OSPF/IS-IS, EIGRP uses a composite metric (not hop count), and it does perform automatic neighbor discovery via hello packets.

  16. 16. A router's routing table contains a default route (0.0.0.0/0) and a more specific route to 192.168.1.0/24. A packet destined for 192.168.1.50 arrives. Which route does the router use?

    • A. The default route, since it is always checked first
    • B. The 192.168.1.0/24 route, because routers use longest prefix match
    • C. Both routes are used simultaneously via load balancing
    • D. Neither route; the packet is dropped as ambiguous
    Show answer & explanation

    Answer: B
    Routers apply the longest prefix match rule, selecting the most specific matching route regardless of administrative distance or metric, so the /24 route is chosen over the /0 default route. The default route is only used as a last resort when no more specific match exists, and there is no ambiguity requiring the packet to be dropped.

  17. 17. An engineer configures inter-VLAN routing using a single router interface with subinterfaces, each tagged for a different VLAN via 802.1Q encapsulation. What is this configuration commonly called?

    • A. Proxy ARP routing
    • B. Switched virtual interface routing
    • C. HSRP routing
    • D. Router-on-a-stick
    Show answer & explanation

    Answer: D
    Router-on-a-stick describes a single physical router interface divided into VLAN-tagged subinterfaces to route between VLANs over one trunk link to a switch. Switched virtual interfaces (SVIs) are a different approach used on Layer 3 switches, proxy ARP is unrelated to VLAN routing, and HSRP provides gateway redundancy, not inter-VLAN routing itself.

  18. 18. A client's DHCP lease is about to expire. At what point in the DHCP lease lifecycle does the client first attempt unicast renewal directly with the original DHCP server?

    • A. Immediately upon receiving the lease, before any time has elapsed
    • B. At approximately 50% of the lease duration (the T1 timer)
    • C. Only after the lease has fully expired
    • D. At exactly 100% of the lease duration
    Show answer & explanation

    Answer: B
    At the T1 timer, roughly 50% of the lease duration, the client sends a unicast DHCPREQUEST directly to the original server to renew the lease before it expires. If that fails, the client waits until T2 (about 87.5%) to broadcast for any server, and only after full expiration does it restart the full DHCP discovery process from scratch.

  19. 19. An organization configures NAT overload (PAT) on its edge router so that all internal hosts share a single public IP address. How does the router distinguish return traffic belonging to different internal hosts?

    • A. It relies on the internal hosts' hostnames advertised via DNS
    • B. It uses unique source port numbers assigned per translated session, tracked in the NAT translation table
    • C. It uses the source MAC address embedded in the IP header
    • D. It assigns a different public IP to each session automatically
    Show answer & explanation

    Answer: B
    PAT (NAT overload) maps each internal host's session to the single public IP but assigns a unique source port, and the router tracks the IP:port combination in its translation table to correctly demultiplex returning traffic. MAC addresses are not carried in IP headers, PAT specifically avoids needing multiple public IPs, and hostnames/DNS play no role in the translation table lookup.

  20. 20. A network administrator wants all switches and routers to synchronize their clocks to a common accurate time source for consistent log timestamps. Which protocol accomplishes this?

    • A. SNMP
    • B. NTP (Network Time Protocol)
    • C. CDP
    • D. TFTP
    Show answer & explanation

    Answer: B
    NTP synchronizes device clocks against a reference time source (often in a hierarchy of stratum levels), ensuring consistent, correlatable timestamps across logs and security events. SNMP is used for monitoring/management, CDP discovers directly connected Cisco devices, and TFTP is a simple file transfer protocol, none of which perform time synchronization.

  21. 21. First Hop Redundancy Protocols (FHRPs) like HSRP provide which primary benefit to hosts on a LAN segment?

    • A. Faster DNS resolution for internal hosts
    • B. A virtual default gateway IP that remains reachable even if the active router fails
    • C. Automatic VLAN tagging on access ports
    • D. Compression of Layer 2 broadcast traffic
    Show answer & explanation

    Answer: B
    HSRP and similar FHRPs present a shared virtual IP/MAC as the default gateway; if the active router fails, a standby router takes over the virtual address so hosts experience no gateway outage. FHRPs do not perform DNS resolution, VLAN tagging, or broadcast compression—those are unrelated functions handled by other protocols or devices.

  22. 22. A security team wants to restrict inbound traffic to only allow TCP port 443 to a specific web server, while denying all other inbound traffic to that host. Which tool is most appropriate to implement this on a Cisco router?

    • A. A standard ACL matching only source addresses
    • B. An extended ACL matching destination IP and destination port 443
    • C. Port security limiting MAC addresses per switchport
    • D. DHCP snooping trust configuration
    Show answer & explanation

    Answer: B
    Extended ACLs can filter on source/destination IP, protocol, and port number, making them the correct tool to permit only HTTPS (port 443) to a specific destination while denying everything else. Standard ACLs only match source address (not destination or port), port security controls which MAC addresses can use a switchport (unrelated to IP traffic filtering), and DHCP snooping guards against rogue DHCP servers, not general traffic filtering.

  23. 23. Which statement accurately describes the security purpose of DHCP snooping on a switch?

    • A. It encrypts DHCP traffic between clients and servers
    • B. It load-balances DHCP requests across multiple servers
    • C. It builds a binding table of trusted IP-to-MAC-to-port mappings and blocks DHCP responses from untrusted ports, mitigating rogue DHCP servers
    • D. It automatically assigns static IP addresses to prevent DHCP use entirely
    Show answer & explanation

    Answer: C
    DHCP snooping designates ports as trusted or untrusted, only allowing DHCP server responses (OFFER/ACK) from trusted ports, and builds a binding table used by related features like Dynamic ARP Inspection; this prevents rogue or unauthorized DHCP servers from handing out malicious configurations. It does not encrypt traffic, does not eliminate DHCP usage, and is not a load-balancing mechanism.

  24. 24. An organization wants to enforce that only known, authorized MAC addresses can transmit traffic on specific access ports, and that the switch should disable the port if a violation occurs. Which feature should be configured?

    • A. BPDU filtering
    • B. Port security with a violation mode of shutdown
    • C. Root guard
    • D. 802.1Q trunking
    Show answer & explanation

    Answer: B
    Port security allows administrators to define allowed MAC addresses per port and specify a violation action; 'shutdown' mode err-disables the port when an unauthorized MAC is detected. Trunking configures VLAN tagging (unrelated to MAC restriction), root guard protects STP root placement, and BPDU filtering suppresses BPDU exchange, neither of which restricts MAC addresses.

  25. 25. Which best describes the difference between authentication and authorization in an AAA (Authentication, Authorization, Accounting) framework?

    • A. Authentication verifies who a user is; authorization determines what that user is permitted to do
    • B. Authentication only applies to wireless networks, authorization only to wired networks
    • C. Authorization verifies identity; authentication determines permitted actions
    • D. Authentication and authorization are the same process performed twice for redundancy
    Show answer & explanation

    Answer: A
    In AAA, authentication confirms a user's or device's identity (e.g., via credentials), while authorization determines the specific resources, commands, or privileges granted to that authenticated identity. The two are distinct sequential steps, not redundant duplicates, and both apply broadly across wired and wireless network access, not exclusively to one medium.

  26. 26. A company wants remote employees to securely access internal resources over the public internet as if they were on the local network. Which technology is designed for this purpose?

    • A. A VPN (Virtual Private Network) using protocols such as IPsec
    • B. VLAN trunking between remote sites
    • C. Spanning Tree Protocol
    • D. CDP neighbor discovery
    Show answer & explanation

    Answer: A
    A VPN, commonly using IPsec, creates an encrypted tunnel over the public internet so remote users can securely reach internal network resources as though locally connected. VLAN trunking extends VLANs across switches on the same administrative network (not designed for internet-based remote access), STP prevents Layer 2 loops, and CDP simply discovers directly connected Cisco devices—neither provides secure remote access.

  27. 27. Which wireless security standard is considered insecure and should be avoided due to fundamentally broken encryption key handling?

    • A. WPA2 with 802.1X
    • B. WPA3-Enterprise
    • C. WEP (Wired Equivalent Privacy)
    • D. WPA2-AES (CCMP)
    Show answer & explanation

    Answer: C
    WEP uses a static, easily-crackable RC4 key scheme with known cryptographic weaknesses, making it insecure by modern standards and unsuitable for production use. WPA2-AES and WPA2 with 802.1X use much stronger AES-based encryption and dynamic key derivation, and WPA3-Enterprise is the current strongest standard with forward secrecy, so none of these share WEP's vulnerabilities.

  28. 28. A network automation script needs to retrieve structured configuration data from a router and modify a specific interface's description without manually parsing free-form CLI text output. Which approach is best suited for this task?

    • A. Screen-scraping 'show running-config' output with regular expressions over an SSH session
    • B. Using a model-driven API such as RESTCONF or NETCONF with structured data formats like YANG/JSON
    • C. Manually telnetting into the device and typing commands interactively
    • D. Relying solely on SNMP traps for configuration changes
    Show answer & explanation

    Answer: B
    RESTCONF and NETCONF expose structured, model-driven (YANG-based) data that can be reliably queried and modified programmatically without fragile text parsing, making them the modern standard for network automation. Screen-scraping CLI output is fragile and error-prone, manual Telnet sessions aren't automatable and Telnet itself is insecure, and SNMP traps are event notifications, not a mechanism for making configuration changes.

  29. 29. In network automation, what is the primary advantage of a declarative configuration management approach (e.g., stating desired end-state) over an imperative approach (e.g., a sequence of CLI commands)?

    • A. Declarative approaches only work with proprietary Cisco hardware
    • B. Declarative approaches cannot be version controlled
    • C. Declarative approaches let the engineer define the desired end state, and the tool determines how to achieve and maintain it, improving consistency and idempotency
    • D. Declarative approaches require the engineer to specify every step needed to reach the end state
    Show answer & explanation

    Answer: C
    Declarative tools (e.g., Ansible playbooks describing desired state) let the automation engine figure out the necessary steps and reapply them idempotently, whereas imperative scripts require explicitly ordered commands and don't inherently guarantee the same end result if run repeatedly. Declarative tools are not limited to Cisco hardware, and configuration files (declarative or not) are commonly stored in version control systems like Git.

  30. 30. A DevOps team wants to represent their network topology and VLAN assignments as version-controlled text files that automatically generate device configurations. Which practice does this describe?

    • A. Infrastructure as Code (IaC)
    • B. Port mirroring
    • C. Spanning Tree PortFast
    • D. Static NAT translation
    Show answer & explanation

    Answer: A
    Infrastructure as Code treats network and infrastructure definitions as versioned, text-based artifacts (e.g., YAML or JSON) that drive automated configuration generation and deployment, enabling repeatability and change tracking. Port mirroring copies traffic for monitoring, PortFast speeds up STP transition on access ports, and static NAT maps a fixed IP translation—none relate to representing infrastructure as version-controlled code.

  31. 31. Which data format is most commonly used by modern network automation tools (e.g., Ansible playbooks) due to its human-readable, indentation-based structure?

    • A. BGP MRT format
    • B. YAML
    • C. 802.1Q tag format
    • D. Binary ASN.1
    Show answer & explanation

    Answer: B
    YAML's clean, indentation-based syntax makes it highly readable for humans while remaining machine-parsable, which is why tools like Ansible use it extensively for playbooks and variable files. Binary ASN.1 is a compact encoding used in protocols like SNMP (not human-friendly), MRT is a binary format for routing table dumps, and 802.1Q tagging is a Layer 2 frame format unrelated to automation data serialization.

  32. 32. A candidate is preparing to schedule the CCNA 200-301 exam and wants to know how the exam is typically delivered. Which statement is accurate?

    • A. It can only be taken at a Pearson VUE Authorized Test Center and never remotely
    • B. It is delivered through Pearson VUE, either at an authorized test center or online via the OnVUE proctored service
    • C. It is self-graded with no proctoring required
    • D. It is delivered exclusively through a Cisco-owned testing platform unrelated to Pearson VUE
    Show answer & explanation

    Answer: B
    Cisco uses Pearson VUE as its authorized delivery provider, offering the CCNA 200-301 both at physical test centers and remotely through the OnVUE online-proctored option with a live remote proctor. The exam is not self-graded or unproctored, and it is not delivered through a separate Cisco-only platform.

  33. 33. A candidate wants to take the CCNA 200-301 exam remotely from home using OnVUE. What is the minimum internet connection speed required for this option?

    • A. 1 Mbps download and 1 Mbps upload
    • B. 6 Mbps download and 2 Mbps upload
    • C. 25 Mbps download and 10 Mbps upload
    • D. No minimum speed is required, only a stable connection
    Show answer & explanation

    Answer: B
    OnVUE's published requirement is a minimum of 6 Mbps download and 2 Mbps upload speed to reliably support the live video proctoring and screen-sharing needed during the remote exam session. Lower speeds risk connection drops during proctoring, and there is a defined minimum rather than no requirement at all; the other listed speeds do not match the published minimum.

  34. 34. After passing the CCNA 200-301 exam, how long does the resulting certification remain valid before recertification is required?

    • A. 5 years
    • B. 3 years
    • C. 1 year
    • D. 2 years
    Show answer & explanation

    Answer: B
    The CCNA certification is valid for 3 years from the date it is earned, after which the holder must recertify by passing a current exam or meeting Cisco's continuing education requirements to maintain active status. The other durations do not match Cisco's published validity period for this certification.

  35. 35. A candidate reviewing the CCNA 200-301 exam blueprint wants to prioritize study time toward the domain with the greatest weight on the exam. Which domain should receive the most attention based on official weighting?

    • A. Security Fundamentals
    • B. Network Access
    • C. IP Connectivity
    • D. Automation and Programmability
    Show answer & explanation

    Answer: C
    IP Connectivity is weighted 25%, the highest among the six official domains, covering routing concepts, OSPF, and related topics, making it the domain deserving the greatest study emphasis. Security Fundamentals (15%), Network Access (20%), and Automation and Programmability (10%) are all weighted lower and should receive proportionally less study time.

  36. 36. Two switches are connected by two physical links that must act as one logical link without spanning tree blocking either. What is configured?

    • A. Two separate VLANs, one per link
    • B. BPDU guard on both interfaces
    • C. An EtherChannel bundling the links, which spanning tree then treats as a single logical interface
    • D. Portfast on both interfaces to skip spanning tree
    Show answer & explanation

    Answer: C
    Bundling presents one logical interface to spanning tree, so no member is blocked and the aggregate bandwidth is available. Member interfaces must match in speed, duplex, VLAN membership and trunking mode or the bundle does not form, and negotiation protocol settings must be compatible on both ends.

  37. 37. A switch port connects to a single workstation and takes about thirty seconds to begin forwarding after link-up. What addresses this?

    • A. Enabling PortFast so the port transitions to forwarding immediately, which is safe only where no switch will be connected
    • B. Disabling spanning tree globally on the switch
    • C. Configuring the port as a trunk
    • D. Increasing the port's speed setting
    Show answer & explanation

    Answer: A
    The delay comes from spanning tree's listening and learning states, and PortFast skips them for ports where a loop cannot form. It is paired with BPDU guard so that if a switch is connected anyway, the port err-disables rather than creating the loop the delay existed to prevent.

  38. 38. Two OSPF routers on the same Ethernet segment remain stuck in the two-way state with each other. What does this indicate?

    • A. Normal behaviour between two DROther routers, which form full adjacency only with the designated and backup designated routers
    • B. A mismatch in the hello and dead interval timers
    • C. A mismatch in the area identifier between the neighbours
    • D. An authentication failure between the neighbours
    Show answer & explanation

    Answer: A
    On a broadcast segment, routers that are neither designated nor backup designated remain in two-way with each other by design, exchanging full adjacency only with the DR and BDR to limit the number of adjacencies. Timer, area and authentication mismatches prevent the neighbour relationship forming at all rather than stopping it at two-way.

  39. 39. An OSPF designated router election occurs on a segment. What determines the winner?

    • A. The router with the most interfaces in the area
    • B. The lowest router ID, with priority ignored
    • C. The router that booted most recently
    • D. The highest interface priority, with the highest router ID breaking a tie, and priority zero excluding a router from the election
    Show answer & explanation

    Answer: D
    Priority is compared first and the router ID resolves ties, with priority zero making a router ineligible entirely. The election is not pre-emptive, so a router that would win does not displace an existing designated router until the adjacency is reset, which surprises administrators who raise a priority and expect an immediate change.

  40. 40. A router learns the same destination network through OSPF and through a static route. Which is installed in the routing table?

    • A. The static route, because administrative distance is compared before metric and static routes have a lower default distance
    • B. The OSPF route, because it is dynamically maintained
    • C. Both, load-balanced equally
    • D. Neither, because the conflict causes both to be discarded
    Show answer & explanation

    Answer: A
    Administrative distance ranks the trustworthiness of route sources and is evaluated before any metric, so a directly connected route beats static, which beats OSPF, which beats less trusted sources. Metric comparison applies only among routes from the same source, and a floating static route deliberately raises its distance so it installs only when the dynamic route disappears.

  41. 41. An access control list is written to match the 192.168.8.0/22 range. Which wildcard mask is correct?

    • A. 0.0.3.255
    • B. 0.0.255.255
    • C. 255.255.252.0
    • D. 0.0.0.255
    Show answer & explanation

    Answer: A
    A /22 subnet mask is 255.255.252.0, and the wildcard is its bitwise inverse, giving 0.0.3.255. Wildcards mark bits to ignore rather than bits to match, which is the inverse of a subnet mask, and using the subnet mask directly in an access list is one of the most common configuration errors.

  42. 42. A standard access control list is applied to filter traffic. Where should it be placed and why?

    • A. Close to the destination, because a standard list matches only the source address and placing it near the source would block that source's traffic to every destination
    • B. Close to the source, to discard unwanted traffic as early as possible
    • C. On every router in the path for consistency
    • D. Placement has no effect on the outcome
    Show answer & explanation

    Answer: A
    A standard list cannot express a destination, so filtering near the source would deny that source access to everything rather than to the intended destination. Extended lists match both source and destination and are therefore placed close to the source, where they discard unwanted traffic before it consumes bandwidth across the network.

  43. 43. An access control list is configured with several permit statements and no deny statement. Traffic not matching any permit is dropped. Why?

    • A. An implicit deny any exists at the end of every access list, so anything not explicitly permitted is denied
    • B. The router defaults to denying all traffic on any interface with a list applied
    • C. The list was applied in the wrong direction
    • D. The permit statements were entered in the wrong order
    Show answer & explanation

    Answer: A
    Every access list ends with an invisible deny of all traffic, which is why a list containing only deny statements blocks everything rather than permitting the remainder. Statements are also evaluated top down with the first match applying, so a broad permit placed above a specific deny makes the deny unreachable.

  44. 44. Many internal hosts share a single public address for internet access. Which translation method is in use?

    • A. Proxy ARP, which answers ARP requests on behalf of another host
    • B. Static NAT, which maps one inside address to one outside address permanently
    • C. Port address translation, which multiplexes many inside addresses onto one outside address by tracking source ports
    • D. Dynamic NAT, which maps inside addresses to a pool one to one
    Show answer & explanation

    Answer: C
    Port address translation, also called NAT overload, distinguishes sessions by port number so a single public address serves many hosts. Static NAT is used to publish an internal server at a fixed public address, and dynamic NAT exhausts once the pool is consumed because it does not multiplex.

  45. 45. Clients on a subnet with no local DHCP server must obtain addresses from a central server. What must be configured on the router interface?

    • A. A helper address forwarding the broadcast DHCP discovery as a unicast to the server
    • B. A static route to the DHCP server's subnet
    • C. An access list permitting DHCP traffic
    • D. A secondary IP address on the interface
    Show answer & explanation

    Answer: A
    DHCP discovery is a broadcast that routers do not forward, so the relay converts it to a unicast toward the configured server and inserts the receiving interface's address so the server selects the correct scope. Routing and permitting the traffic are prerequisites but neither causes the broadcast to cross the router.

  46. 46. A switch port configured with port security detects a violation. What does the default violation mode do?

    • A. Shutdown, placing the port into an error-disabled state requiring manual or automatic recovery before it forwards again
    • B. Protect, silently discarding frames from unknown addresses
    • C. Restrict, discarding frames and incrementing a counter with notification
    • D. Permit, logging the event and continuing to forward
    Show answer & explanation

    Answer: A
    The default is shutdown, which err-disables the port and stops all traffic until recovery, whereas protect discards silently and restrict discards while logging and counting. Configuring error-disable recovery with a timer avoids a truck roll for every violation, and sticky learning lets legitimate addresses be captured into the running configuration automatically.

  47. 47. A trunk link carries VLANs 10, 20 and 30, and VLAN 1 is the native VLAN. How is native VLAN traffic transmitted?

    • A. Untagged, while the other VLANs are tagged, and a native VLAN mismatch between the two ends merges those VLANs
    • B. Tagged like all other VLANs on the trunk
    • C. Not carried at all across a trunk
    • D. Carried on a separate physical link automatically
    Show answer & explanation

    Answer: A
    Native VLAN frames traverse the trunk without a tag, so a mismatch causes each side to place the other's untagged traffic into a different VLAN, bridging two VLANs together silently. Changing the native VLAN away from the default and ensuring both ends agree is standard practice for exactly this reason.

  48. 48. Hosts in VLAN 10 and VLAN 20 must communicate. What is required?

    • A. A layer 3 device routing between the VLANs, whether a router subinterface or a switched virtual interface on a multilayer switch
    • B. A trunk link between the two access switches
    • C. Placing both VLANs on the same physical switch
    • D. Enabling spanning tree on both VLANs
    Show answer & explanation

    Answer: A
    VLANs are separate broadcast domains and therefore separate IP subnets, so traffic between them must be routed. A trunk carries multiple VLANs between switches but does not move traffic between them, which is why hosts on the same switch in different VLANs still cannot communicate without a routing device.

  49. 49. A wireless deployment uses lightweight access points and a controller. What protocol carries traffic between them?

    • A. CAPWAP, which tunnels both control and data traffic between the access point and the controller
    • B. SNMP, which carries management polling
    • C. RADIUS, which carries authentication requests
    • D. NTP, which carries time synchronization
    Show answer & explanation

    Answer: A
    CAPWAP forms separate control and data tunnels, letting the controller manage configuration, radio resources and client roaming centrally. RADIUS carries authentication between the controller and an identity server, which is a different exchange, and an access point that cannot reach its controller cannot serve clients in a purely centralized design.

  50. 50. A wireless network uses WPA2-Enterprise. What differs from WPA2-Personal?

    • A. Each user authenticates individually through 802.1X against a RADIUS server rather than sharing a pre-shared key
    • B. Enterprise uses a longer pre-shared key
    • C. Enterprise disables encryption in favour of authentication
    • D. Personal supports more simultaneous clients
    Show answer & explanation

    Answer: A
    Individual credentials mean a departing employee is revoked centrally without rekeying every device, which a shared key cannot achieve. Enterprise also derives unique session keys per client, so one client cannot decrypt another's traffic even on the same network, which is a limitation of pre-shared key mode.

  51. 51. An IPv6 address begins with FE80. What type of address is this and what is its scope?

    • A. A link-local address, valid only on the local link and not routable beyond it
    • B. A global unicast address routable across the internet
    • C. A multicast address delivered to a group
    • D. A unique local address routable within an organization
    Show answer & explanation

    Answer: A
    Link-local addresses are automatically configured on every IPv6 interface and are used for neighbour discovery and as the next hop in routing, which is why routing protocol adjacencies form over them. Global unicast addresses begin with 2000 through 3FFF, unique local with FC00 or FD00, and multicast with FF.

  52. 52. A network engineer retrieves device configuration through a REST API returning JSON. What characterizes this data format?

    • A. Key-value pairs with nested objects and arrays, parsed natively by most languages, using braces for objects and square brackets for arrays
    • B. Fixed-width columns with positional field meaning
    • C. Tag-delimited markup requiring a schema to parse
    • D. Binary encoding requiring a vendor-specific decoder
    Show answer & explanation

    Answer: A
    JSON's structure of objects and arrays maps directly onto native data structures in common scripting languages, which is why it dominates modern network APIs. XML uses tag-delimited markup and YAML uses indentation, and all three represent similar hierarchical data with different syntax and readability trade-offs.

  53. 53. A team adopts a configuration management tool that describes the desired device state rather than the commands to reach it. What is this approach called?

    • A. Declarative configuration, where the tool determines the actions needed to converge the device on the described state
    • B. Imperative configuration, where each command is specified in order
    • C. Manual configuration through the command line
    • D. Reactive configuration triggered by device alerts
    Show answer & explanation

    Answer: A
    Declarative tooling makes runs idempotent, so applying the same description twice produces no additional change, which is what allows configuration to be reapplied safely to detect and correct drift. Imperative scripting executes steps regardless of current state, so rerunning it can fail or duplicate work.

  54. 54. A controller-based network architecture separates control from forwarding. What role does the northbound interface play?

    • A. It exposes the controller's capabilities to applications and orchestration systems, typically as a REST API
    • B. It carries configuration from the controller down to network devices
    • C. It connects the controller to the internet service provider
    • D. It synchronizes time across the control plane
    Show answer & explanation

    Answer: A
    Northbound faces applications while southbound faces the devices, so an application requests an outcome through the northbound API and the controller implements it through southbound protocols. That separation is what lets business systems drive network behaviour without knowing any device syntax.

  55. 55. A router's syslog output must be sent to a central collector with accurate timestamps. Which two configurations are needed?

    • A. A syslog server destination and NTP synchronization, since correlated analysis depends on consistent time across devices
    • B. A syslog destination alone, since devices timestamp independently
    • C. SNMP community strings and an access list
    • D. A DHCP pool and a default route
    Show answer & explanation

    Answer: A
    Logs from devices with divergent clocks cannot be sequenced into a coherent account of an incident, so time synchronization is as necessary as the log destination. Severity levels also matter, since configuring a level that includes debugging can flood both the device and the collector during a busy period.

  56. 56. SNMP is configured for monitoring. Which version should be selected and why?

    • A. Any version, since SNMP traffic is confined to the management network
    • B. Version 1, because it is the most widely supported
    • C. Version 2c, because it adds encryption to version 1
    • D. Version 3, because it provides authentication and encryption, whereas earlier versions transmit community strings in clear text
    Show answer & explanation

    Answer: D
    Versions 1 and 2c authenticate with a community string sent in clear text, and a read-write string obtained by an observer permits reconfiguring the device. Version 2c added bulk retrieval and improved error handling but no security, which is the distinction most often misremembered.

  57. 57. Quality of service is applied on a WAN link carrying voice and bulk data. Which treatment suits voice?

    • A. A low-latency priority queue with policing, since voice needs bounded delay and jitter and gains nothing from buffering
    • B. The largest available buffer, so no voice packet is ever dropped
    • C. The same treatment as bulk data for fairness
    • D. Shaping to delay voice until bulk transfers complete
    Show answer & explanation

    Answer: A
    A voice packet arriving late is useless, so buffering converts loss into delay that damages the call further, which is why voice is served from a strictly prioritized queue. Policing the priority queue prevents voice traffic from starving everything else if its volume exceeds what was provisioned.

  58. 58. A network engineer must verify that a routing change did not remove reachability to a remote subnet. Which verification is most direct?

    • A. Checking the routing table for the expected prefix and confirming end-to-end reachability from a host in the affected subnet
    • B. Confirming the interface counters have not incremented
    • C. Reviewing the device's configuration file for syntax errors
    • D. Verifying the device's uptime is unchanged
    Show answer & explanation

    Answer: A
    The routing table shows what the device will actually do with a packet, which the configuration only implies, and testing from an affected host validates the whole path rather than one device's view. Testing from the router itself can succeed where a host fails, because the router's source address and return path may differ from the host's.

  59. 59. A first hop redundancy protocol is configured on two routers serving a subnet. What do clients use as their default gateway?

    • A. A virtual IP address shared between the routers, which the active router answers and the standby assumes on failure
    • B. The physical address of the active router, reconfigured on clients when it fails
    • C. Both physical addresses, alternated by the client
    • D. The subnet broadcast address
    Show answer & explanation

    Answer: A
    Clients hold one static gateway address, so redundancy requires that address to move rather than clients being reconfigured, which the virtual address provides. Failover is transparent to clients because the virtual MAC address moves with the virtual IP, so no ARP cache update is needed on every host.

  60. 60. A device management plane must be protected. Which practice applies to virtual terminal lines?

    • A. Restricting access with an access class, requiring SSH rather than Telnet, and applying an idle timeout
    • B. Leaving them open so administrators can always connect in an emergency
    • C. Using a shared account so credentials do not need distribution
    • D. Disabling logging on management sessions to reduce noise
    Show answer & explanation

    Answer: A
    Restricting which source addresses may connect, requiring encrypted transport and timing out idle sessions together reduce the exposure of the management plane. Shared accounts destroy attribution, and disabling session logging removes the record needed to determine what an administrator or an intruder actually did.

  61. 61. Authentication for device administrators is centralized. What does AAA provide beyond a single login?

    • A. Encryption of all traffic through the device
    • B. Authentication of identity, authorization of permitted commands, and accounting recording what was executed
    • C. Only authentication, with the other functions handled locally
    • D. Only accounting of session durations
    Show answer & explanation

    Answer: B
    Centralizing all three means an administrator's permitted command set and their activity record follow their identity rather than the device, so revoking access once takes effect everywhere. Command accounting is what makes it possible to answer who changed a configuration, which local authentication with a shared enable password cannot.

  62. 62. DHCP snooping is enabled on an access switch. What attack does it mitigate?

    • A. A rogue DHCP server offering addresses and a malicious default gateway, by permitting DHCP responses only from trusted ports
    • B. A denial of service flood against the switch's CPU
    • C. Unauthorized physical access to the wiring closet
    • D. Password guessing against the switch management interface
    Show answer & explanation

    Answer: A
    A rogue server can hand clients its own address as the gateway and observe all their traffic, and snooping blocks server responses arriving on untrusted access ports. The binding table snooping builds also underpins dynamic ARP inspection and source guard, so it is a prerequisite for those protections rather than only a standalone control.

  63. 63. An interface shows a high count of cyclic redundancy check errors. What class of problem does this indicate?

    • A. A physical layer problem such as a damaged cable, faulty transceiver or electrical interference corrupting frames in transit
    • B. A routing protocol misconfiguration
    • C. An access list denying the traffic
    • D. Insufficient bandwidth on the link
    Show answer & explanation

    Answer: A
    A failed checksum means the frame arrived corrupted, which is a signalling problem rather than a logical one, so cabling, connectors, transceivers and interference are the places to look. Congestion produces output drops rather than input errors, so the counter type distinguishes a physical fault from a capacity problem.

  64. 64. An interface shows late collisions on a full-duplex link. What is the likely cause?

    • A. A duplex mismatch, where one end operates half duplex and the other full duplex
    • B. An excessively long cable within specification
    • C. A VLAN misconfiguration on the port
    • D. An outdated routing table entry
    Show answer & explanation

    Answer: A
    Collisions should not occur at all on a full-duplex link, so their presence means the peer believes the link is half duplex and is applying collision detection. The symptom is a link that passes small amounts of traffic while performing terribly under load, which is why duplex mismatches are diagnosed from counters rather than from reachability tests.

  65. 65. A network diagram must be validated against reality before a change. Which device feature helps discover directly connected neighbours?

    • A. A layer 2 discovery protocol reporting neighbouring devices, their platform, and the connecting ports on each side
    • B. The routing table, which lists reachable networks
    • C. The MAC address table, which lists learned addresses per port
    • D. The DHCP binding table, which lists assigned leases
    Show answer & explanation

    Answer: A
    Neighbour discovery protocols report which device is on the other end of each link and through which port, which is exactly what verifies a diagram. The MAC address table shows learned addresses without identifying the device, and it also lists addresses reached through intermediate switches rather than only direct neighbours.

  66. 66. An engineer studying the TCP/IP model wants to know which single layer of that model maps to the presentation and session responsibilities described by the OSI reference model. Which TCP/IP layer absorbs those functions?

    • A. Internet
    • B. Transport
    • C. Network access
    • D. Application
    Show answer & explanation

    Answer: D
    The four-layer TCP/IP model folds the OSI application, presentation, and session layers into one application layer, so encryption formatting and dialog management live there. The transport layer maps to OSI Layer 4, the internet layer maps to OSI Layer 3, and the network access layer covers OSI Layers 1 and 2.

  67. 67. While segmenting an application transfer, host Aria-PC adds a sequence number and destination port to the data before handing it down the stack. Which protocol data unit has Aria-PC just created?

    • A. A packet
    • B. A segment
    • C. A frame
    • D. A bit stream
    Show answer & explanation

    Answer: B
    Port numbers and sequence numbers belong to the transport layer, and the transport layer PDU is called a segment. A packet is formed later when the IP header is added, a frame is formed at the data link layer with MAC addressing, and bits are the physical layer representation on the wire.

  68. 68. A consultant reviewing an addressing plan notices a point-to-point WAN link configured as 10.203.113.4/30. Which two addresses on that link can actually be assigned to the router interfaces?

    • A. 10.203.113.6 and 10.203.113.7
    • B. 10.203.113.4 and 10.203.113.7
    • C. 10.203.113.4 and 10.203.113.5
    • D. 10.203.113.5 and 10.203.113.6
    Show answer & explanation

    Answer: D
    A /30 contains four addresses where the first is the network number and the last is the broadcast, leaving .5 and .6 as the two usable interface addresses. Any pairing that includes .4 assigns the network address, and any pairing that includes .7 assigns the broadcast, both of which are invalid for interfaces.

  69. 69. A NOC technician can ping the default gateway from workstation PC-14 but cannot load an internal web application, and a packet capture shows the TCP three-way handshake completing followed by an HTTP 500 response. At which layer of the OSI model is the fault most likely occurring?

    • A. Network layer
    • B. Data link layer
    • C. Application layer
    • D. Transport layer
    Show answer & explanation

    Answer: C
    Successful pings prove Layers 1 through 3, and a completed three-way handshake proves the transport layer is working end to end. An HTTP 500 code is a server-side application error, so the problem sits at the application layer. Transport, network, and data link faults would prevent the handshake or the ping from succeeding in the first place.

  70. 70. A frame arrives at router Edge-R2, which strips the Ethernet header, examines the destination IPv4 address, and forwards the packet out a serial interface with a new Layer 2 encapsulation. Which OSI layer is Edge-R2 using to make its forwarding decision?

    • A. Data link layer
    • B. Physical layer
    • C. Session layer
    • D. Network layer
    Show answer & explanation

    Answer: D
    Routers make forwarding decisions by comparing the destination IP address against the routing table, which is a network layer function. The data link layer is only rewritten hop by hop, not used to choose the exit interface, the physical layer just moves bits, and the session layer manages dialogs between end applications, not packet forwarding.

  71. 71. A switch named AccessSw-3 floods a received unicast frame out every port in the same VLAN except the ingress port. What causes this behavior?

    • A. The destination MAC address is not in the switch MAC address table
    • B. The frame failed its frame check sequence validation
    • C. Spanning tree has placed all other ports in a blocking state
    • D. The destination IP address is outside the local subnet
    Show answer & explanation

    Answer: A
    When a switch has no MAC table entry for a frame's destination, it performs unknown unicast flooding so the frame still reaches its owner, and the eventual reply lets the switch learn the address. A frame that fails the FCS check is discarded rather than flooded, switches do not examine destination IP addresses when forwarding, and blocking ports would prevent flooding rather than cause it.

  72. 72. Two directly connected hosts on the same subnet can exchange ARP replies, but a protocol analyzer shows every TCP connection attempt between them being reset immediately by the receiving host. Which layer should the engineer investigate first?

    • A. Layer 2, because the switch has likely learned the wrong MAC address
    • B. Layer 1, because the cable is probably producing late collisions
    • C. Layer 3, because the subnet mask on one host must be wrong
    • D. Layer 4, because a host firewall may be rejecting the destination port
    Show answer & explanation

    Answer: D
    Working ARP proves Layers 1 through 3 are healthy between the hosts, so an immediate TCP reset points to something refusing the connection at the transport layer, most often a host-based firewall or a closed port. Cable faults or wrong MAC learning would break ARP as well, and a mask error would prevent the hosts from attempting direct delivery in the first place.

  73. 73. A technician must connect two buildings 320 meters apart with a link that is immune to electrical interference from a nearby industrial plant. Which cabling choice satisfies both requirements?

    • A. Multimode fiber-optic cable
    • B. Category 6 UTP copper
    • C. Shielded twisted-pair copper
    • D. Coaxial cable
    Show answer & explanation

    Answer: A
    Fiber carries light rather than electrical signals, so it is unaffected by electromagnetic interference and easily spans 320 meters, which multimode optics handle comfortably. All copper Ethernet variants, shielded or not, are limited to 100 meters per segment and remain susceptible to strong interference, and coax is neither a standard modern LAN medium nor rated for that distance in Ethernet designs.

  74. 74. The counters on interface GigabitEthernet0/1 of switch Dist-A show a steadily increasing number of CRC errors and input errors, while output errors remain at zero. What is the most likely cause?

    • A. An MTU mismatch with the neighboring device
    • B. A speed setting that is higher than the attached device supports
    • C. A duplex mismatch causing the interface to defer transmissions
    • D. A damaged cable or failing transceiver corrupting inbound frames
    Show answer & explanation

    Answer: D
    CRC errors mean frames are arriving with checksums that do not match their contents, which points to physical-path damage such as a bad cable, connector, or transceiver. A duplex mismatch typically shows late collisions rather than pure CRC growth, an MTU mismatch produces giants or drops rather than checksum failures, and a hard speed mismatch usually keeps the link from coming up at all.

  75. 75. A campus uplink is described as running 1000BASE-T. Which statement about this link is accurate?

    • A. It runs gigabit Ethernet over single-mode fiber up to 5 kilometers
    • B. It runs gigabit Ethernet over four pairs of twisted-pair copper up to 100 meters
    • C. It runs 100 megabit Ethernet over two pairs of copper
    • D. It runs 10 gigabit Ethernet over short-reach multimode fiber
    Show answer & explanation

    Answer: B
    In IEEE shorthand the leading number is the speed in megabits and the T suffix means twisted-pair copper, so 1000BASE-T is gigabit over copper using all four pairs with the standard 100 meter reach. Single-mode long-reach gigabit is 1000BASE-LX, 100 megabit copper is 100BASE-TX, and short-reach 10 gigabit fiber is 10GBASE-SR.

  76. 76. A network engineer sees the message '%LINEPROTO-5-UPDOWN: Line protocol on Interface GigabitEthernet0/2, changed state to down' while the physical interface status remains up. What does this combination indicate?

    • A. The interface was administratively disabled by a configuration change
    • B. The physical layer is functional but a Layer 2 problem such as keepalive or encapsulation failure exists
    • C. The cable is unplugged at the far end of the link
    • D. The interface hardware has failed and must be replaced
    Show answer & explanation

    Answer: B
    An interface showing up/down means the port detects electrical signal, so the cable path works, but the data link protocol is not operating, which points at encapsulation mismatches, missed keepalives, or a far-end protocol issue. A disconnected cable would show down/down, an administrative shutdown shows administratively down, and failed hardware would not report the physical layer as up.

  77. 77. A small office uses power over Ethernet to run wireless access points. The facilities team asks why the new AP model will not boot on the old switch even though the cable tests clean. Which explanation is most likely?

    • A. The switch port must be configured as a trunk before PoE will activate
    • B. PoE cannot pass through patch panels, so the AP must connect directly
    • C. The AP requires a crossover cable instead of a straight-through cable
    • D. The AP draws more power than the switch port's PoE standard can supply
    Show answer & explanation

    Answer: D
    PoE standards deliver different wattages, and a newer access point that needs 802.3at or 802.3bt power levels will fail to boot on a switch that only supplies the lower 802.3af budget. Modern interfaces handle crossover automatically with auto-MDIX, PoE passes through standard structured cabling, and trunk configuration is unrelated to whether power is delivered.

  78. 78. A branch office is assigned the network 172.16.4.0/26 for its workstations. How many usable host addresses does this subnet provide, and what is its broadcast address?

    • A. 64 usable hosts with broadcast address 172.16.4.64
    • B. 62 usable hosts with broadcast address 172.16.4.63
    • C. 30 usable hosts with broadcast address 172.16.4.31
    • D. 126 usable hosts with broadcast address 172.16.4.127
    Show answer & explanation

    Answer: B
    A /26 prefix leaves 6 host bits, giving 2 to the sixth power minus 2, which is 62 usable addresses, and the block runs from 172.16.4.0 through 172.16.4.63, making .63 the broadcast. The value 64 counts the raw addresses without subtracting network and broadcast, 30 hosts with .31 describes a /27, and 126 with .127 describes a /25.

  79. 79. Server team member Priya configures a host with the address 172.31.99.201 and mask 255.255.240.0. Which network and broadcast addresses apply to this host?

    • A. Network 172.31.96.0 and broadcast 172.31.111.255
    • B. Network 172.31.99.0 and broadcast 172.31.99.255
    • C. Network 172.31.96.0 and broadcast 172.31.103.255
    • D. Network 172.31.64.0 and broadcast 172.31.127.255
    Show answer & explanation

    Answer: A
    A 255.255.240.0 mask is a /20, so the third octet increments in blocks of 16: 96 through 111. The address 172.31.99.201 therefore falls in network 172.31.96.0 with broadcast 172.31.111.255. Treating it as a /24 gives the .99.0 answer, a /18 would give the 64 through 127 range, and ending the block at .103.255 mistakes the /20 for a /21.

  80. 80. A VLSM design must carve a subnet for a warehouse segment that will hold 500 devices while wasting as few addresses as possible. Which prefix length should the designer choose?

    • A. /24, which supplies 254 usable addresses
    • B. /23, which supplies 510 usable addresses
    • C. /25, which supplies 126 usable addresses
    • D. /22, which supplies 1022 usable addresses
    Show answer & explanation

    Answer: B
    Nine host bits give 510 usable addresses, the smallest power-of-two block that covers 500 devices, and nine host bits corresponds to a /23. A /24 tops out at 254 hosts and is too small, a /22 works but wastes roughly half its space, and a /25 offers only 126 addresses, far below the requirement.

  81. 81. Help desk staff report that host 10.44.17.66/28 cannot reach host 10.44.17.81/28 without a router even though both plug into the same switch. Why is a router required?

    • A. The hosts are in the same subnet but the switch is blocking local traffic
    • B. Addresses ending in .66 and .81 are both broadcast addresses and cannot be assigned
    • C. A /28 mask never allows two hosts to communicate without a router
    • D. The hosts are in different subnets: .66 belongs to 10.44.17.64/28 and .81 belongs to 10.44.17.80/28
    Show answer & explanation

    Answer: D
    With a /28 the block size is 16, so subnets start at .64 and .80. The host at .66 sits in 10.44.17.64/28 while .81 sits in 10.44.17.80/28, and traffic between different subnets always needs a Layer 3 device regardless of the shared switch. The hosts are not in one subnet, neither address is a broadcast (.79 and .95 are), and hosts inside the same /28 communicate directly without routing.

  82. 82. An ISP delegates 203.0.113.0/25 to a customer who subnets it into equal /27 blocks for four small departments. Which statement about the resulting design is correct?

    • A. The /25 cannot be divided into /27 subnets because the boundaries do not align
    • B. The /25 yields exactly four /27 subnets, each with 30 usable addresses
    • C. The /25 yields four /27 subnets, each with 62 usable addresses
    • D. The /25 yields eight /27 subnets, each with 30 usable addresses
    Show answer & explanation

    Answer: B
    Moving from /25 to /27 borrows two bits, creating 2 squared, or exactly 4, subnets at 203.0.113.0, .32, .64, and .96, and each /27 leaves five host bits for 30 usable addresses. Eight subnets would require borrowing three bits, 62 hosts describes a /26, and any shorter prefix divides cleanly into longer prefixes, so alignment is never a problem.

  83. 83. Network operations needs the full range of addresses that a monitoring server may see from the subnet 10.10.32.0/21. Which range of usable addresses should they whitelist?

    • A. 10.10.32.1 through 10.10.47.254
    • B. 10.10.32.1 through 10.10.39.254
    • C. 10.10.32.1 through 10.10.32.254
    • D. 10.10.33.1 through 10.10.40.254
    Show answer & explanation

    Answer: B
    A /21 spans eight third-octet values, so 10.10.32.0/21 covers 10.10.32.0 through 10.10.39.255, making the usable range .32.1 through .39.254. Stopping at 10.10.32.254 treats the network as a /24, extending to .47.254 treats it as a /20, and starting at .33.1 misplaces the block boundary entirely.

  84. 84. An engineer at Helios Logistics wants a single summary route covering the four branch networks 10.4.0.0/16, 10.5.0.0/16, 10.6.0.0/16, and 10.7.0.0/16 without including any other space. Which summary should be advertised?

    • A. 10.4.0.0/16
    • B. 10.0.0.0/13
    • C. 10.4.0.0/14
    • D. 10.4.0.0/15
    Show answer & explanation

    Answer: C
    The four /16 networks form one contiguous block from 10.4.0.0 through 10.7.255.255, which is exactly the span of 10.4.0.0/14 since a /14 covers four consecutive /16s starting on a multiple of 4. A /15 covers only 10.4 and 10.5, a /13 starting at 10.0.0.0 would pull in 10.0 through 10.7 and overreach, and a single /16 covers just one of the branches.

  85. 85. A junior admin claims that assigning 192.168.7.191 to a printer in subnet 192.168.7.160/27 will work fine. How should the senior engineer respond?

    • A. The address must not be used because it is the broadcast address of that subnet
    • B. The address is fine because printers ignore broadcast traffic anyway
    • C. The address must not be used because it is the network address of that subnet
    • D. The address is fine because only .255 addresses are reserved for broadcast
    Show answer & explanation

    Answer: A
    The subnet 192.168.7.160/27 runs from .160 through .191, so .191 is its directed broadcast address and cannot be assigned to a host. Broadcast addresses depend on the mask, not on ending in 255, the network address of this block is .160 rather than .191, and a device's traffic handling never makes a reserved address assignable.

  86. 86. During an audit, an engineer finds a host configured as 172.19.200.77 with mask 255.255.248.0 that cannot reach its gateway at 172.19.196.1. What is the root cause?

    • A. The host address is invalid because .77 is reserved in a /21 network
    • B. The mask 255.255.248.0 is not a legal subnet mask
    • C. The gateway and host are in the same subnet, so the fault must be physical
    • D. The gateway address lies outside the host's subnet, which spans 172.19.200.0 through 172.19.207.255
    Show answer & explanation

    Answer: D
    With a /21 mask the block containing .200.77 runs from 172.19.200.0 through 172.19.207.255, and 172.19.196.1 falls in the previous block, so the host can never ARP for a gateway outside its own subnet. Nothing reserves .77 in any prefix, 255.255.248.0 is a perfectly valid contiguous mask, and because the gateway truly is in a different subnet, the fault is logical rather than physical.

  87. 87. A network designer must write the IPv6 address 2001:0db8:0000:0000:00a9:0000:0000:0930 in its correct fully compressed form. Which representation is valid?

    • A. 2001:db8:0:0:a9::930
    • B. 2001:db8::a9::930
    • C. 2001:db8::a9:0:0:930
    • D. 2001:db8::a9:0:0:93
    Show answer & explanation

    Answer: C
    Leading zeros drop from every group and the double colon may replace only one run of zero groups; when two runs tie in length, compressing the first is the convention, producing 2001:db8::a9:0:0:930. Using two double colons in one address is illegal because the expansion becomes ambiguous, and dropping the trailing zero from 0930 changes the value since only leading zeros may be removed. The form 2001:db8:0:0:a9::930 is an alternative expansion but not the conventional compression of the first zero run.

  88. 88. Host Beacon-7 boots on an IPv6 network and automatically gives itself an address beginning with fe80. What kind of address is this and how far can it communicate?

    • A. A link-local address usable only on the local link and never routed
    • B. A unique local address routable inside the organization only
    • C. A global unicast address routable across the internet
    • D. A multicast address used to reach all routers on the link
    Show answer & explanation

    Answer: A
    Addresses in fe80::/10 are link-local, created automatically on every IPv6 interface and valid only for communication on the directly attached link; routers never forward them. Global unicast space begins at 2000::/3, unique local addresses come from fc00::/7, and the all-routers multicast group is ff02::2, none of which start with fe80.

  89. 89. An engineer enables SLAAC on VLAN 40. Describe how a client workstation on that VLAN obtains a global IPv6 address.

    • A. It learns the prefix from a router advertisement and generates its own interface identifier
    • B. It asks the DNS server to allocate an unused address from the zone file
    • C. It copies the address of the default router and increments the final bit
    • D. It broadcasts a DHCPDISCOVER and receives a full address from a DHCPv6 server
    Show answer & explanation

    Answer: A
    With stateless address autoconfiguration the router advertisement supplies the 64-bit prefix, and the host appends an interface identifier it generates itself, using either random values or the EUI-64 method. DHCPDISCOVER broadcasts belong to DHCPv4 rather than SLAAC, hosts never derive addresses by modifying the router's address, and DNS servers resolve names but play no role in address assignment.

  90. 90. Before using an address produced by autoconfiguration, an IPv6 host sends a neighbor solicitation targeted at its own tentative address. What is the host doing?

    • A. Registering the address with the local router's neighbor table
    • B. Advertising the address so switches can update their MAC tables
    • C. Requesting a prefix delegation from the upstream DHCPv6 server
    • D. Performing duplicate address detection to confirm no other node uses the address
    Show answer & explanation

    Answer: D
    Duplicate address detection works by soliciting your own tentative address; if any node answers, the address is already in use and must not be activated. Routers build neighbor entries from normal traffic rather than registrations, prefix delegation is a separate DHCPv6-PD exchange initiated toward a delegating router, and switch MAC learning happens from source addresses of frames, not from targeted solicitations.

  91. 91. A multinational firm wants internal-only IPv6 addressing for a lab that must never be routed on the public internet, while avoiding conflicts if labs merge later. Which address block fits this purpose?

    • A. Multicast addresses from ff00::/8
    • B. Unique local addresses from fc00::/7
    • C. Link-local addresses from fe80::/10
    • D. Global unicast addresses from 2000::/3
    Show answer & explanation

    Answer: B
    Unique local addresses are the IPv6 counterpart of private addressing: they are routable inside an organization, blocked from the global internet, and built with a random 40-bit global ID that makes collisions between merged networks unlikely. Link-local addresses cannot cross even one router so they cannot serve a routed lab, global unicast is publicly routable, and multicast identifies groups rather than individual lab hosts.

  92. 92. A packet capture on an IPv6 segment shows traffic to ff02::1 and ff02::2. What do these two destinations represent?

    • A. The loopback address and the unspecified address, respectively
    • B. The solicited-node group and the DHCPv6 server group, respectively
    • C. Two anycast addresses assigned to redundant gateways
    • D. All nodes on the link and all routers on the link, respectively
    Show answer & explanation

    Answer: D
    The well-known multicast group ff02::1 reaches every IPv6 node on the local link and ff02::2 reaches every router on the link, filling the role IPv4 broadcasts once played. Solicited-node groups take the form ff02::1:ffxx:xxxx and DHCPv6 uses ff02::1:2, anycast addresses come from ordinary unicast space, and loopback and unspecified are ::1 and :: respectively.

  93. 93. A media startup streams live sports commentary where an occasional lost packet is acceptable but added delay is not. The developers also need application-level framing with no retransmission. Which transport protocol matches these needs?

    • A. UDP, because it avoids connection setup, acknowledgments, and retransmission delays
    • B. TCP, because its sequencing guarantees the commentary arrives in order
    • C. UDP, because it retransmits lost datagrams faster than TCP does
    • D. TCP, because its window scaling eliminates latency on long paths
    Show answer & explanation

    Answer: A
    Real-time audio favors UDP precisely because it sends datagrams with no handshake, no acknowledgment waiting, and no retransmission stalls, keeping latency low while tolerating small losses. TCP's ordering and reliability introduce delay that damages live streams, UDP performs no retransmission at all, and window scaling improves TCP throughput but cannot remove retransmission-induced latency.

  94. 94. During a TCP connection setup between client Nova-PC and a database server, the client sends a segment with the SYN flag and an initial sequence number of 4820. What does the server send in the second step of the handshake?

    • A. A segment with the RST flag set and its own initial sequence number
    • B. A segment with the FIN flag set to complete the exchange
    • C. A segment with SYN and ACK flags set and an acknowledgment number of 4821
    • D. A segment with only the ACK flag set acknowledging sequence 4820
    Show answer & explanation

    Answer: C
    The middle step of the three-way handshake is a SYN-ACK: the server proposes its own initial sequence number and acknowledges the client's by adding one, hence 4821. A bare ACK is the client's third step, FIN begins connection teardown rather than setup, and RST would abort the attempt instead of continuing it.

  95. 95. An application vendor complains that its transfers slow down whenever the network drops packets, while a colleague's UDP-based telemetry keeps a constant rate. What TCP mechanism explains the slowdown?

    • A. Congestion control shrinks the sending window when segment loss is detected
    • B. The urgent pointer forces retransmitted data ahead of new data
    • C. The push flag suspends transmission until the receiver empties its buffer
    • D. TCP checksums require every segment to be verified twice
    Show answer & explanation

    Answer: A
    TCP treats loss as a congestion signal and reduces its transmission window, then grows it again gradually, so throughput dips after drops; UDP has no such feedback loop and keeps blasting at the application's rate. The urgent pointer only marks priority bytes within the stream, checksums are computed once per segment, and the push flag asks for prompt delivery rather than pausing the sender.

  96. 96. A firewall administrator must permit inbound requests to a server running HTTPS, plus zone transfers and standard queries for the DNS service on the same box. Which port and protocol set is correct?

    • A. TCP 443 for HTTPS, with DNS using UDP 53 exclusively for every operation
    • B. TCP 443 for HTTPS, with DNS using UDP 53 for queries and TCP 53 for zone transfers
    • C. TCP 80 for HTTPS, with DNS using UDP 69 for queries
    • D. UDP 443 for HTTPS, with DNS using TCP 53 for all traffic
    Show answer & explanation

    Answer: B
    HTTPS listens on TCP 443, and DNS is the classic dual-transport service: ordinary lookups ride UDP 53 while zone transfers and oversized responses use TCP 53. HTTPS does not traditionally run over UDP 443 in this context, port 80 is unencrypted HTTP and 69 is TFTP, and restricting DNS to UDP would break the required zone transfers.

  97. 97. Two applications on the same laptop, a browser and a mail client, hold simultaneous connections to the same remote server address. How does the laptop's TCP/IP stack keep the returning traffic separated?

    • A. The server tags each stream with a distinct VLAN identifier
    • B. Each application is assigned its own MAC address for the session
    • C. The stack alternates delivery between the applications in round-robin order
    • D. Each connection uses a different local port number, so the socket tuples remain unique
    Show answer & explanation

    Answer: D
    A connection is identified by the pair of IP addresses and the pair of port numbers; because each client application opened its own ephemeral source port, the tuples differ and the stack demultiplexes returning segments unambiguously. Hosts do not mint per-application MAC addresses, VLAN tags are a switching construct invisible to server-side session separation, and delivery follows the socket identifiers rather than any rotation scheme.

  98. 98. A coffee shop deploys three access points on the 2.4 GHz band and users report severe interference. The APs are set to channels 2, 5, and 8. What should the engineer change?

    • A. Raise the transmit power on all three APs so clients hear them more clearly
    • B. Move the APs to channels 1, 6, and 11, the only nonoverlapping 2.4 GHz channels
    • C. Set all three APs to channel 6 so they share one clean frequency
    • D. Enable channel bonding to combine the three channels into one wide channel
    Show answer & explanation

    Answer: B
    In the 2.4 GHz band each channel is wide enough to overlap its neighbors, so only channels 1, 6, and 11 avoid mutual interference; channels 2, 5, and 8 partially overlap each other, which is worse than co-channel operation. Raising power amplifies the interference, putting every AP on one channel forces constant contention, and bonding in 2.4 GHz consumes most of the band and aggravates the problem.

  99. 99. A site survey report notes that the 5 GHz band was chosen for a dense office deployment instead of 2.4 GHz. Which characteristic of 5 GHz justifies that choice?

    • A. It supports only one client per channel, guaranteeing dedicated bandwidth
    • B. It is immune to interference from radar and other outdoor systems
    • C. It offers many more nonoverlapping channels, allowing dense AP placement with less co-channel interference
    • D. It penetrates walls and floors better than 2.4 GHz, extending coverage
    Show answer & explanation

    Answer: C
    The 5 GHz band provides a large set of nonoverlapping channels, so many APs can operate near each other on distinct frequencies, which is exactly what dense deployments need. Higher frequencies actually attenuate more through walls rather than less, parts of the band must yield to radar through dynamic frequency selection, and any Wi-Fi channel is shared contention-based airtime rather than a per-client reservation.

  100. 100. A wireless engineer explains that every SSID broadcast by an access point radio is paired with a unique MAC-like identifier used in frame addressing. What is this identifier called?

    • A. The ESSID
    • B. The BSSID
    • C. The distribution system identifier
    • D. The radio MIB handle
    Show answer & explanation

    Answer: B
    Each basic service set is identified by a BSSID, a MAC-format value tied to the AP radio for that SSID, and clients use it to address frames within the cell. The ESSID is simply the extended network name shared by multiple APs, the distribution system is the wired backbone connecting APs rather than an identifier in frames, and MIB handles belong to SNMP management, not 802.11 addressing.

  101. 101. Guests in a hotel lobby roam between two access points that advertise the same WLAN name and security settings while wired together through the LAN. What 802.11 topology does this describe?

    • A. An ad hoc mesh network
    • B. An extended service set
    • C. A point-to-point wireless bridge
    • D. An independent basic service set
    Show answer & explanation

    Answer: B
    Multiple access points sharing one SSID over a common distribution system form an extended service set, which is what lets clients roam without reassociating to a new network name. An independent basic service set is an ad hoc, AP-free topology, mesh describes APs relaying traffic wirelessly rather than through wired LAN, and a wireless bridge joins two wired segments rather than serving roaming clients.

  102. 102. Employees complain of slow Wi-Fi in a conference room even though signal strength is excellent. The engineer finds a legacy 802.11b barcode scanner associated to the same 2.4 GHz radio. Why can one slow device degrade the whole cell?

    • A. Legacy clients force the AP to disable all security, causing retransmissions
    • B. Airtime is shared, so slow-rate transmissions occupy the channel far longer for the same data
    • C. The scanner's traffic is copied to every other client as broadcast frames
    • D. The AP reserves half of its power budget for the oldest associated client
    Show answer & explanation

    Answer: B
    Wi-Fi is a shared medium where only one station transmits at a time, so a device sending at very low legacy rates consumes a disproportionate share of airtime, leaving little for fast clients regardless of their signal quality. APs do not partition power budgets per client, security settings are not dropped for legacy stations, and unicast scanner traffic is never duplicated to other clients.

  103. 103. A data center runs a hypervisor installed directly on server hardware with no underlying operating system, hosting a dozen guest machines. Which virtualization model is in use?

    • A. Operating-system-level containers
    • B. A type 1 bare-metal hypervisor
    • C. Hardware emulation through a terminal server
    • D. A type 2 hosted hypervisor
    Show answer & explanation

    Answer: B
    A hypervisor running directly on the physical hardware is type 1, the bare-metal model favored in data centers for efficiency and isolation. Type 2 hypervisors run as applications on top of a host operating system, containers share one kernel rather than running separate guest machines, and terminal servers deliver remote sessions rather than hardware virtualization.

  104. 104. A developer notes that her application ships as containers rather than virtual machines. Compared with VMs, what is a defining property of containers?

    • A. They share the host operating system kernel instead of each carrying a full guest OS
    • B. They each boot their own dedicated kernel for stronger hardware isolation
    • C. They cannot be assigned individual IP addresses on the network
    • D. They require a type 1 hypervisor to schedule their CPU time
    Show answer & explanation

    Answer: A
    Containers package applications with their libraries but execute on the shared kernel of the host, which is why they start quickly and consume little memory compared with virtual machines that boot entire guest operating systems. Booting a dedicated kernel is precisely what containers avoid, they are managed by a container engine rather than a hypervisor, and container networking readily assigns individual addresses.

  105. 105. Traffic between two virtual machines on the same physical host reaches its destination without ever leaving the server. What component makes this possible?

    • A. The physical top-of-rack switch hairpins the frames back into the host
    • B. The guest operating systems exchange memory pages directly without networking
    • C. A virtual switch running in the hypervisor connects the VMs' virtual NICs
    • D. A VLAN trunk between the VMs eliminates the need for switching
    Show answer & explanation

    Answer: C
    Hypervisors include a virtual switch that connects each VM's virtual NIC; frames between co-resident VMs are switched in software inside the host and never touch the physical wire. Hairpinning through the physical switch happens only in specific designs where the vSwitch is bypassed, a trunk is a link configuration rather than a forwarding engine, and VMs communicate through networking, not raw shared memory.

  106. 106. A service provider must let two customers with overlapping 10.0.0.0/8 addressing share one physical router while keeping their routes completely separate. Which technology accomplishes this?

    • A. Static NAT translating one customer's entire address space at every hop
    • B. Virtual routing and forwarding instances that give each customer an isolated routing table
    • C. Proxy ARP configured on the shared customer-facing interfaces
    • D. A second loopback interface dedicated to the overlapping prefixes
    Show answer & explanation

    Answer: B
    VRF instances create independent routing tables on one physical router, so identical prefixes from different customers coexist without conflict, each bound to its own interfaces. A loopback is a single interface rather than a separation mechanism, proxy ARP answers ARP requests and does nothing for route isolation, and per-hop NAT of an entire /8 is neither scalable nor a routing separation technique.

  107. 107. An operations team moves a workload from a single physical server to a virtual machine on a shared cluster and wants to understand the main resource trade-off. Which statement is accurate?

    • A. The virtual machine will always run faster because virtualization removes the operating system layer
    • B. Virtualization removes the need for network configuration inside the guest
    • C. The hypervisor introduces a small overhead, but the cluster gains flexibility such as live migration and higher hardware utilization
    • D. Each virtual machine must be assigned a whole physical CPU socket to function
    Show answer & explanation

    Answer: C
    Virtualization trades a modest scheduling and I/O overhead for large operational wins: workloads consolidate onto fewer boxes, and features like live migration and snapshots become possible. The guest still runs a full operating system so nothing is removed, guests still need normal network configuration, and vCPUs are scheduled onto shared cores rather than requiring dedicated sockets.

  108. 108. Finance users on switch AccessSw-9 sit in VLAN 30 and engineering users sit in VLAN 45. A finance workstation tries to ping an engineering workstation attached to the same switch and fails. What is required for this communication to succeed?

    • A. Both VLANs must be added to the switch's allowed list on every access port
    • B. The workstations must share a common default VLAN membership first
    • C. A Layer 3 device must route between VLAN 30 and VLAN 45
    • D. The switch needs a second uplink so the VLANs can bridge through it
    Show answer & explanation

    Answer: C
    Each VLAN is its own broadcast domain and its own subnet, so traffic between VLAN 30 and VLAN 45 must be routed by a Layer 3 switch or a router regardless of the shared chassis. Allowed lists apply to trunk links rather than access ports, forcing both hosts into one VLAN changes the design rather than enabling inter-VLAN traffic, and a second uplink cannot bridge separate broadcast domains by itself.

  109. 109. A technician issues 'show vlan brief' on switch Warehouse-Sw and sees port Gi0/7 listed under VLAN 1 even though the port was supposed to serve VLAN 120. The VLAN 120 line is missing entirely from the output. What happened?

    • A. VLAN 120 was never created, so the switchport access command could not take effect
    • B. The port failed authentication and fell back to the guest VLAN
    • C. The port is a trunk, so it will never appear under a specific VLAN
    • D. VLAN 120 exists but is hidden because it carries no traffic yet
    Show answer & explanation

    Answer: A
    Assigning a port to a VLAN that does not exist leaves the port in its current VLAN on some platforms or inactive on others, and the missing row in 'show vlan brief' confirms VLAN 120 was never defined on this switch. Trunk ports are indeed absent from the per-VLAN listing, but that would not explain the missing VLAN row; VLANs appear in the output whether or not they carry traffic, and authentication fallback requires an 802.1X configuration the scenario never mentions.

  110. 110. A data center team needs to aggregate links between a Cisco switch and a third-party vendor's switch. Which bundling protocol should they select and why?

    • A. PAgP, because it automatically detects the other vendor's hardware
    • B. DTP, because it negotiates both trunking and aggregation together
    • C. UDLD, because it verifies both directions of every member link
    • D. LACP, because it is the IEEE standard supported across vendors
    Show answer & explanation

    Answer: D
    LACP is standardized as part of IEEE link aggregation, so it interoperates between different vendors' equipment, making it the right choice for a mixed environment. PAgP is Cisco proprietary and unavailable on other vendors, DTP negotiates trunking rather than aggregation, and UDLD detects unidirectional links but does not form bundles.

  111. 111. The design for the Brookfield campus calls for phones and PCs to share single access ports, with phone traffic isolated in its own VLAN. Which configuration accomplishes this?

    • A. Configure the data VLAN with switchport access vlan and add switchport voice vlan for the phones
    • B. Configure the port as a full 802.1Q trunk allowing only the two VLANs
    • C. Assign both devices to the same VLAN and separate them with port security
    • D. Enable a private VLAN so the phone and PC cannot see each other
    Show answer & explanation

    Answer: A
    The voice VLAN feature lets an access port carry one untagged data VLAN for the PC and one tagged VLAN for the phone, which is the standard IP telephony design. A general-purpose trunk works electrically but is not the recommended access-edge practice and complicates security features, a single shared VLAN abandons the isolation requirement, and private VLANs control peer-to-peer visibility rather than creating a separate voice network.

  112. 112. After a maintenance window, users connected to ports Gi0/10 through Gi0/20 of switch Atrium-Sw2 lost connectivity. The interfaces show 'inactive' in status output, and the technician recalls deleting an unused VLAN from the database that evening. What is the most likely cause?

    • A. The VLAN database change erased the port channel configuration
    • B. The ports negotiated themselves into trunks when the VLAN was removed
    • C. Deleting any VLAN resets all access ports to the default VLAN automatically
    • D. The deleted VLAN was still assigned to those ports, which become inactive when their VLAN disappears
    Show answer & explanation

    Answer: D
    When a VLAN is deleted while ports still reference it, those ports do not fall back to VLAN 1; they go inactive and pass no traffic until the VLAN is recreated or they are reassigned. Removing a VLAN does not flip ports into trunking mode, ports are never automatically reassigned to the default VLAN on deletion, and the VLAN database is independent of EtherChannel configuration.

  113. 113. A security consultant recommends that switch management traffic be moved out of VLAN 1 on every access switch at Delta Freight. What is the primary reason for this practice?

    • A. Switches cannot apply access lists to interfaces in VLAN 1
    • B. VLAN 1 frames are always sent untagged and therefore cannot be encrypted
    • C. VLAN 1 has lower forwarding priority than other VLANs in hardware
    • D. VLAN 1 is the default for every port and many protocols, so separating management reduces exposure to user-side attacks
    Show answer & explanation

    Answer: D
    Because every port defaults to VLAN 1 and control traffic often rides it, leaving management there mixes user reachability with the management plane; moving management to a dedicated VLAN shrinks the attack surface. Hardware forwards all VLANs with equal priority, ACLs apply to any SVI including VLAN 1, and tagging status has nothing to do with the ability to encrypt management sessions.

  114. 114. Switch NorthSw-1 has ports in VLANs 10, 20, and 30 but no switched virtual interfaces defined except interface VLAN 99, which carries its management address. What Layer 3 capability does this switch currently provide to attached hosts?

    • A. It routes between VLANs 10, 20, and 30 using its VLAN 99 address
    • B. None; it switches frames within each VLAN and hosts must use an external gateway for routing
    • C. It translates VLAN tags so the three VLANs behave as one broadcast domain
    • D. It proxies ARP between the VLANs so hosts believe they share a subnet
    Show answer & explanation

    Answer: B
    An SVI provides a routed interface for its own VLAN only; with just the management SVI present, the switch performs no inter-VLAN routing and hosts in VLANs 10, 20, and 30 must point at a router or Layer 3 switch elsewhere. One SVI in VLAN 99 cannot serve as a gateway for other VLANs, proxy ARP across VLANs is not a default switch behavior, and VLAN translation does not merge broadcast domains this way.

  115. 115. At a shared office park, tenants Alpha and Beta each need their broadcast traffic contained even though both connect through the same access switch stack. How do VLANs meet this requirement?

    • A. VLANs limit each tenant to a fixed number of broadcasts per second
    • B. VLANs compress broadcast frames so they consume negligible bandwidth
    • C. Each VLAN forms a separate broadcast domain, so broadcasts from one tenant never reach the other's ports
    • D. VLANs convert broadcast frames into unicasts directed at the gateway
    Show answer & explanation

    Answer: C
    A VLAN bounds the flooding scope of broadcasts, multicasts, and unknown unicasts, so putting each tenant in its own VLAN keeps their broadcast traffic fully separated at Layer 2. VLANs neither compress frames, rewrite broadcasts as unicasts, nor apply rate limits; those behaviors belong to other features entirely.

  116. 116. A new intern asks why the output of 'show interfaces status' on switch Lakeview-A displays some ports with a specific VLAN number and others with the word 'trunk' in the VLAN column. What explains the difference?

    • A. Numbered ports are Layer 3 routed ports and trunk ports are Layer 2
    • B. Ports showing a number carry one access VLAN, while ports showing trunk carry multiple tagged VLANs
    • C. Ports showing a number are shut down and the number is their error code
    • D. The word trunk indicates the port failed VLAN assignment and defaulted
    Show answer & explanation

    Answer: B
    The VLAN column reports the operating mode: an access port displays its single VLAN membership, while a trunk port displays the word trunk because it transports many VLANs with 802.1Q tags. The number is a VLAN ID rather than an error code, trunk is a deliberate mode rather than a failure state, and routed ports show up differently rather than as VLAN numbers.

  117. 117. An 802.1Q trunk connects switches Mercury-1 and Mercury-2 with native VLAN 99 on both ends. A frame belonging to VLAN 99 is sent across this trunk. How is it transmitted?

    • A. It is dropped, because native VLAN traffic is not permitted on trunks
    • B. Untagged, because native VLAN traffic crosses an 802.1Q trunk without a tag
    • C. With a double tag so the far switch can verify the native VLAN
    • D. With a standard tag of 99 like any other VLAN's traffic
    Show answer & explanation

    Answer: B
    802.1Q defines the native VLAN as the one whose frames traverse the trunk untagged; the receiving switch assigns untagged arrivals to its own native VLAN. Double tagging is an attack technique rather than normal operation, tagging the native VLAN happens only when a specific tagging option is enabled, and native traffic is forwarded, not dropped.

  118. 118. Switches Quartz-A and Quartz-B are joined by a trunk where Quartz-A uses native VLAN 10 and Quartz-B uses native VLAN 20. CDP is logging native VLAN mismatch messages. What operational problem can this mismatch create?

    • A. Untagged frames sent from one switch are placed into a different VLAN on the other switch, merging traffic between VLANs 10 and 20
    • B. The trunk link physically shuts down until the mismatch is corrected
    • C. All tagged VLANs on the trunk stop forwarding while the native VLANs disagree
    • D. The switches renegotiate the trunk into an access port in VLAN 1
    Show answer & explanation

    Answer: A
    Untagged frames leaving Quartz-A belong to VLAN 10 but arrive at Quartz-B and are dropped into VLAN 20, silently leaking traffic between two VLANs that should be isolated; spanning tree may also block per-VLAN. The link itself stays up, tagged VLANs continue to forward normally since their membership is explicit, and a native mismatch never converts a trunk into an access port.

  119. 119. A trunk between switch Cobalt-3 and a virtualization host must carry only VLANs 110, 120, and 130 and must never negotiate. Which configuration approach is correct on the switch port?

    • A. Set the mode to trunk, disable DTP negotiation, and prune the allowed list to 110, 120, and 130
    • B. Set the port to access mode in VLAN 110 and let the host tag 120 and 130
    • C. Set the mode to dynamic desirable and list the three VLANs as native
    • D. Leave the mode dynamic auto and create the three VLANs in the database
    Show answer & explanation

    Answer: A
    The requirement calls for a statically formed trunk with negotiation disabled through the nonegotiate function, plus an allowed VLAN list limited to the three needed IDs; this is the standard secure server-trunk pattern. Dynamic desirable actively negotiates, dynamic auto forms a trunk only if the far side initiates and prunes nothing, and an access port in one VLAN discards the tagged traffic for the other two.

  120. 120. Interface Gi0/24 on switch Pine-1 runs dynamic auto, and the far end on switch Pine-2 is also set to dynamic auto. Both were expected to form a trunk carrying several VLANs, yet each port settled into access mode. Why?

    • A. Dynamic auto is incompatible with 802.1Q and only supports untagged links
    • B. Dynamic auto ports only respond to negotiation, so with neither side initiating, no trunk forms
    • C. One port must be configured as native before negotiation can start
    • D. Both switches must first have identical VLAN databases before trunking
    Show answer & explanation

    Answer: B
    Dynamic auto is passive: it will become a trunk if the neighbor requests one, but never asks on its own, so two passive ends both wait forever and default to access operation. The mode fully supports 802.1Q once negotiated, VLAN database parity is not a precondition for trunk formation, and native VLAN settings adjust tagging rather than gating negotiation.

  121. 121. A voice engineer reviewing 'show interfaces trunk' on switch Falcon-2 sees VLAN 150 listed under allowed VLANs but missing from the 'allowed and active' section. What does this indicate?

    • A. The trunk's encapsulation rejects VLAN IDs above 128
    • B. VLAN 150 is the native VLAN and is therefore listed separately
    • C. VLAN 150 traffic is being rate limited due to congestion on the trunk
    • D. VLAN 150 is permitted on the trunk but does not exist or is suspended on this switch
    Show answer & explanation

    Answer: D
    The active list is the intersection of the allowed list with VLANs that actually exist and are active in the VLAN database, so a permitted but missing VLAN drops out of that section. Rate limiting does not alter trunk listings, the native VLAN still appears among active VLANs when it exists, and 802.1Q supports VLAN IDs up to 4094, so 150 is well within range.

  122. 122. During a change window, an engineer types the command to set the allowed VLAN list on an existing production trunk to 'vlan 300' and immediately triggers outages for other departments. What did the engineer most likely do wrong?

    • A. Created a native VLAN mismatch by allowing a VLAN below 1000
    • B. Disabled spanning tree on the trunk by modifying the list
    • C. Exceeded the maximum number of VLANs a single trunk supports
    • D. Replaced the entire allowed list with only VLAN 300 instead of adding it with the add keyword
    Show answer & explanation

    Answer: D
    Specifying an allowed list without the add keyword overwrites the whole list, so every other VLAN was instantly removed from the trunk and their users cut off; the correct syntax appends VLAN 300 to the existing set. Native VLAN mismatches are unrelated to list edits, trunks carry far more than the handful of VLANs involved, and modifying allowed lists never disables spanning tree.

  123. 123. An attacker in VLAN 10 crafts frames with two 802.1Q tags, hoping a switch will strip the outer tag and forward the frame into VLAN 60 without routing. Which condition makes this VLAN hopping technique possible?

    • A. The switch runs rapid spanning tree instead of legacy spanning tree
    • B. The attacker's access port is in the same VLAN as the trunk's native VLAN, so the outer tag matches the untagged VLAN
    • C. The trunk between switches has all VLANs in its allowed list
    • D. The target VLAN 60 has no SVI configured on the switch
    Show answer & explanation

    Answer: B
    Double tagging works only when the outer tag equals the trunk's native VLAN: the first switch strips that outer tag as ordinary native traffic and forwards the still-tagged frame, which the next switch places into VLAN 60. A permissive allowed list widens what a trunk carries but is not the enabling condition, spanning tree versions have no bearing on tag processing, and SVI presence relates to routing rather than tag stripping.

  124. 124. Switch Iris-1's ports Gi0/1-2 run channel-group mode active while the connected ports on switch Iris-2 run mode passive. What is the result?

    • A. A static channel forms without any protocol negotiation
    • B. An LACP EtherChannel forms because active initiates negotiation and passive responds
    • C. No channel forms because passive ports ignore LACP entirely
    • D. A PAgP channel forms because the modes are from different protocols
    Show answer & explanation

    Answer: B
    Active and passive are both LACP modes; an active end sends LACPDUs and a passive end answers them, so the bundle negotiates successfully. Passive ports do process received LACP frames, PAgP uses the desirable and auto keywords rather than these, and a protocol-free static bundle would require mode on at both ends.

  125. 125. An engineer bundles four uplinks between distribution switches Summit-A and Summit-B using channel-group mode on at both ends, but sets one member port to a different speed. What is the likely outcome?

    • A. The channel renegotiates to LACP to accommodate the difference
    • B. The mismatched port is suspended from the bundle because member interfaces must have identical settings
    • C. The entire channel fails and all four physical links shut down
    • D. The bundle averages the speeds and runs all links at the combined rate
    Show answer & explanation

    Answer: B
    EtherChannel members must match on speed, duplex, VLAN configuration, and mode; a nonconforming interface is excluded or suspended while the rest of the bundle keeps working. Bandwidth is not averaged across mismatched members, mode on never negotiates a protocol by itself, and one bad member does not administratively shut down the healthy links.

  126. 126. After building a two-link EtherChannel, an engineer notices that a single large backup flow between two servers uses only one physical member and never exceeds 1 Gbps despite the 2 Gbps bundle. Why?

    • A. The servers must also bundle their NICs before the channel splits flows
    • B. The second link is a hot standby that activates only if the first fails
    • C. The load-balancing hash assigns each flow to one member link, so a single flow cannot span both
    • D. EtherChannel reserves half the bundle for control traffic
    Show answer & explanation

    Answer: C
    EtherChannel hashes header fields like MAC or IP addresses to choose one member per flow, keeping packets in order; a single conversation therefore rides one physical link and tops out at that link's speed. Members are all active rather than standby, no capacity is reserved for control traffic, and server-side NIC teaming changes nothing about how the switch hashes an individual flow.

  127. 127. The command 'show etherchannel summary' on switch Onyx-4 displays port-channel Po2 with the flags SD, and its member ports show the lowercase flag s. How should the engineer interpret this?

    • A. The port channel is a Layer 2 bundle that is currently down, with members suspended
    • B. The bundle is up and forwarding on all suspended members simultaneously
    • C. Po2 is a Layer 3 channel operating in standby mode by design
    • D. The output shows a healthy channel; those flags are informational only
    Show answer & explanation

    Answer: A
    In this summary, capital S marks a Layer 2 channel and D means it is down, while the lowercase s on members means suspended, typically from configuration mismatches or a failed negotiation. Suspended members never forward, standby operation is not what these letters encode, and a healthy bundle would show flags indicating in-use members instead.

  128. 128. A campus architect explains that bundling uplinks with EtherChannel between access and distribution switches has a side benefit related to spanning tree. What is that benefit?

    • A. Spanning tree is disabled automatically on aggregated interfaces
    • B. Spanning tree treats the bundle as one logical link, so no member is blocked and all links carry traffic
    • C. The bundle becomes immune to topology changes elsewhere in the network
    • D. Spanning tree converges faster because BPDUs replicate across every member
    Show answer & explanation

    Answer: B
    Because STP sees the port channel as a single interface, redundant physical uplinks that would otherwise be blocked are all used, multiplying usable bandwidth while retaining redundancy. BPDU replication across members is not how convergence improves, topology changes elsewhere still affect the bundle's role, and spanning tree remains active on port channels rather than being disabled.

  129. 129. Four switches at Ridgeline Corp run per-VLAN spanning tree with default priorities. Switch Rid-2 has the lowest MAC address of the four. What role will Rid-2 assume and why?

    • A. Root bridge, because with equal priorities the lowest MAC address wins the election
    • B. Designated bridge for every segment, because low MACs get all designated roles
    • C. Backup root, because MAC address is only the second tiebreaker after uptime
    • D. Edge bridge, because the lowest MAC is excluded from the root election
    Show answer & explanation

    Answer: A
    The root election compares bridge IDs, which combine priority and MAC address; with priorities tied at the default, the lowest MAC address produces the lowest bridge ID and wins. Uptime never enters the election, designated roles on each segment are decided by path cost to the root rather than granted wholesale, and no bridge is excluded from candidacy.

  130. 130. An engineer wants switch Core-West to always win the spanning tree root election for VLAN 200, guarding against any new switch joining with a low MAC address. What should be configured?

    • A. Lower the spanning tree priority for VLAN 200 on Core-West to a value below all other switches
    • B. Raise the hello timer on Core-West so it advertises more frequently
    • C. Configure all other switches with the same priority as Core-West
    • D. Assign Core-West the highest priority value available for VLAN 200
    Show answer & explanation

    Answer: A
    Deterministic root placement comes from lowering the priority, since a lower bridge ID always beats any MAC address comparison; the root primary macro does the same thing. Hello timers affect BPDU cadence rather than election outcomes, the highest priority value makes a switch the least likely root, and equalizing priorities reintroduces the MAC-address lottery the engineer wants to avoid.

  131. 131. Switch Aspen-3 has two uplinks toward the root bridge: one 1 Gbps link through a neighbor and one 10 Gbps link through a different neighbor, with all other values equal. Which port becomes the root port?

    • A. The port on the 1 Gbps path, because slower links are preferred for control traffic
    • B. The port on the 10 Gbps path, because its lower cumulative path cost to the root wins
    • C. Whichever port has the higher interface number on Aspen-3
    • D. Both ports forward and share the load toward the root
    Show answer & explanation

    Answer: B
    Root port selection minimizes cumulative cost to the root, and faster links carry lower cost values, so the 10 Gbps path wins when everything else is equal. Slower links are never preferred, interface numbers act only as a final tiebreaker on parallel links from the same neighbor, and classic spanning tree keeps exactly one root port forwarding, never a load-shared pair.

  132. 132. Users report a 30 second outage each time their PC reboots on legacy spanning tree switch ports without any optimization features. What causes this specific delay?

    • A. The port must pass through listening and forwarding delay states before it forwards traffic
    • B. The switch waits for the PC to complete duplicate address detection
    • C. The DHCP server intentionally delays offers to newly linked ports
    • D. The port negotiates its speed for 30 seconds before going active
    Show answer & explanation

    Answer: A
    Classic 802.1D moves a newly up port through listening and learning, each lasting the 15 second forward delay, totaling roughly 30 seconds before frames pass; this is precisely what edge-port features were created to skip. Duplicate address detection is an IPv6 host function measured in seconds at most, DHCP servers respond as soon as discovery arrives, and speed negotiation completes in moments rather than half a minute.

  133. 133. A network administrator enables PortFast on interface Fa0/12 of switch Meadow-1 where a file server connects. Weeks later someone plugs a small switch into that port. What risk does this create and which feature mitigates it?

    • A. A loop could form because PortFast skips the normal checks; BPDU guard should be enabled to shut the port if a BPDU arrives
    • B. The port floods all VLANs; storm control must rewrite the port to access mode
    • C. The server loses its VLAN because switches cannot share PortFast ports; root guard restores it
    • D. Nothing changes, because PortFast automatically disables itself when a switch connects
    Show answer & explanation

    Answer: A
    PortFast assumes a single end host and forwards immediately, so an accidentally attached switch could complete a loop before topology detection catches up; BPDU guard errdisables the port the moment any BPDU is heard, containing the mistake. VLAN membership is unaffected by what device plugs in, storm control limits flooding rates rather than changing port modes, and PortFast does not self-disable when it detects a switch.

  134. 134. In a rapid spanning tree topology, switch Birch-2's root port fails. An alternate port on Birch-2 had been discarding traffic. How does RSTP respond compared with classic 802.1D?

    • A. Birch-2 floods a topology query and waits for the root to assign a new port
    • B. The alternate port becomes a backup port and stays discarding permanently
    • C. The alternate port transitions to root port rapidly without waiting for legacy timers
    • D. Birch-2 must wait the full max-age plus two forward delays before recovery
    Show answer & explanation

    Answer: C
    RSTP precomputes the alternate port as the backup path to the root, so when the root port dies the alternate is promoted almost immediately through the proposal and agreement mechanism rather than timer-based waiting. The multi-timer wait describes classic 802.1D convergence, roots never assign ports to remote switches, and backup ports are a different role that serves shared segments rather than replacements for lost root ports.

  135. 135. Two equal /24 routes to 203.0.113.0 exist on router Aster-R1, one via next hop 10.0.0.2 and one via 10.0.0.6, both learned by OSPF with identical costs. How does Aster-R1 treat traffic to that network?

    • A. It alternates between routes every thirty seconds to balance wear
    • B. It uses only the route learned first and holds the second in reserve
    • C. It rejects both routes until an administrator selects one manually
    • D. It installs both routes and load-shares packets across the two next hops
    Show answer & explanation

    Answer: D
    Equal-cost multipath is standard behavior: identical prefixes with matching metrics from the same protocol both install, and the forwarding plane distributes flows across the next hops. Order of learning does not create a standby relationship, no timed alternation mechanism exists, and routers never require manual selection between valid equal routes.

  136. 136. An engineer examining a switch running rapid PVST+ sees a port labeled with the backup role in spanning tree output. What does the backup role indicate?

    • A. The port is a redundant connection to a shared segment that the same switch already serves with a designated port
    • B. The port carries BPDUs only and never user data under any condition
    • C. The port takes over as root port whenever the primary experiences errors
    • D. The port is the second-best path to the root through a different neighboring switch
    Show answer & explanation

    Answer: A
    A backup port exists when a switch has two connections onto the same shared segment, backing up its own designated port there, which is rare in modern point-to-point networks. The second-best path through another switch describes the alternate role instead, promotion targets differ by role, and while a discarding backup port passes no user data currently, its definition concerns the segment relationship rather than a BPDU-only function.

  137. 137. A broadcast storm brings down the Pinehill office LAN. Investigators find that a contractor looped a patch cable between two wall jacks feeding the same switch, and spanning tree had been disabled for a lab test. Why did this loop escalate so severely?

    • A. The looped cable doubled the switch's MAC table capacity and overflowed it
    • B. Ethernet frames carry no hop count, so broadcasts circulated endlessly and multiplied until the network saturated
    • C. Broadcast frames convert to multicast in loops, which switches cannot filter
    • D. The loop reversed frame check sequences, causing every frame to be resent
    Show answer & explanation

    Answer: B
    Unlike IP packets with their TTL, Layer 2 frames have no aging field, so in a loop every broadcast is reflooded forever while new broadcasts join, growing exponentially until links and CPUs choke; this is exactly the failure spanning tree exists to prevent. MAC table capacity does not double from a loop, broadcasts remain broadcasts, and FCS values are unrelated to retransmission behavior.

  138. 138. Two switches, Vale-1 and Vale-2, are linked twice with no bundling configured, and spanning tree is running. A junior tech asks why 'show spanning-tree' on Vale-2 shows one of the two ports in a blocking state. What should the senior tech answer?

    • A. Spanning tree intentionally blocks one redundant link to break the loop while keeping it as a failover path
    • B. The blocked port has a hardware fault and should be replaced promptly
    • C. The two links have mismatched native VLANs, so one link cannot forward
    • D. The switch blocks the newer link until it has been up for one full day
    Show answer & explanation

    Answer: A
    Two parallel links between the same switches form a physical loop, so spanning tree elects one port to forward and puts the other in a blocking or discarding state, holding it ready to take over on failure; this is normal, healthy operation. No hardware fault is implied, native VLAN mismatches generate different symptoms and log messages, and no uptime-based blocking rule exists.

  139. 139. A field technician connects to switch Dune-5 and needs the management IP address and platform of the directly attached upstream Cisco switch without logging into it. Which command provides this detail?

    • A. show ip arp
    • B. show mac address-table
    • C. show cdp neighbors detail
    • D. show interfaces description
    Show answer & explanation

    Answer: C
    The detailed CDP neighbor output lists each adjacent Cisco device's hostname, platform, capabilities, and management address, exactly what the technician needs. The MAC table maps addresses to ports without identifying devices, the ARP table maps IPs to MACs for hosts the switch itself communicates with, and interface descriptions show only locally entered text.

  140. 140. A consultant compares autonomous access points with controller-based lightweight APs for a client with 300 sites. What is the main operational argument for the controller-based design at this scale?

    • A. Configuration, RF tuning, and policy are centralized, avoiding per-AP management of thousands of devices
    • B. Autonomous APs cannot support more than one SSID per radio
    • C. Controller-based APs do not require PoE, simplifying cabling
    • D. Lightweight APs transmit at higher power than autonomous models
    Show answer & explanation

    Answer: A
    At large scale the decisive benefit is central management: controllers push configuration, coordinate channels and power, and apply consistent security everywhere, while autonomous APs must each be configured and monitored individually. Autonomous APs support multiple SSIDs, transmit power is a regulatory and hardware matter rather than an architecture one, and both AP types commonly draw PoE.

  141. 141. A security audit at Harbor Bank requires that switches stop advertising device details on all ports facing user desks, while an IP phone deployment still depends on discovery information from those same ports. The phones support the IEEE standard protocol. What should the engineer do?

    • A. Disable both discovery protocols globally, because phones do not use them
    • B. Disable CDP on user-facing ports and rely on LLDP with appropriate TLVs where phones need discovery, controlling it per port
    • C. Replace discovery with SNMP polling from the phones to the switch
    • D. Leave CDP enabled everywhere, because discovery cannot be disabled per port
    Show answer & explanation

    Answer: B
    Discovery protocols can be toggled per interface, so the audit is satisfied by disabling the proprietary protocol on desk ports and using the IEEE standard LLDP, with its media extensions, only where the phones require it. Phones genuinely depend on discovery for VLAN and power details, per-port control absolutely exists, and phones do not learn their voice VLAN through SNMP polling.

  142. 142. An engineer runs a neighbor discovery command on router Mesa-R1 and sees a neighbor entry naming switch Mesa-Sw3, local interface Gi0/0, and port ID Gi1/0/14. What does this tell the engineer?

    • A. Gi1/0/14 is Mesa-R1's own interface renamed by the discovery protocol
    • B. Mesa-R1's Gi0/0 connects directly to port Gi1/0/14 on Mesa-Sw3
    • C. Mesa-Sw3 is reachable through routing but is several hops away
    • D. Mesa-Sw3 is advertising a default route to Mesa-R1 on that port
    Show answer & explanation

    Answer: B
    Discovery protocols operate only between directly connected devices, and the output pairs the local interface with the neighbor's port, so the physical adjacency is Gi0/0 on the router to Gi1/0/14 on the switch. Multi-hop devices never appear as neighbors, the port ID column always describes the remote end rather than a local rename, and discovery advertisements carry identity information, never routes.

  143. 143. A data center standardizes on LLDP instead of CDP across mixed-vendor racks. Which behavioral detail should the team keep in mind about LLDP?

    • A. It floods advertisements through switches so devices learn distant neighbors
    • B. It cannot convey management addresses, so CDP must stay on for that
    • C. It transmits neighbor data only when solicited by a management station
    • D. It is an IEEE standard that works across vendors but typically must be enabled on Cisco switches, where CDP runs by default
    Show answer & explanation

    Answer: D
    LLDP delivers vendor-neutral discovery, but on Cisco platforms the default-on protocol is CDP, so LLDP generally needs explicit enabling globally or per interface. LLDP advertises periodically on its own rather than answering polls, its TLVs do include management addresses, and advertisements are consumed by the adjacent device rather than flooded onward.

  144. 144. Bayside College deploys 240 lightweight access points managed by a pair of wireless LAN controllers. Which protocol do the APs use to communicate with their controller, and how does it operate?

    • A. SNMP, which the controller uses to poll each AP's configuration once per minute
    • B. GRE, which every AP negotiates with each client individually
    • C. CAPWAP, which builds tunnels between each AP and the controller for control and data traffic
    • D. RADIUS, which encapsulates all wireless frames inside authentication records
    Show answer & explanation

    Answer: C
    Lightweight APs form CAPWAP tunnels to their controller: an encrypted control channel for configuration and management plus a data channel that can carry client traffic centrally. SNMP is a general management protocol rather than the AP-controller channel, RADIUS handles authentication exchanges only, and GRE tunnels are not negotiated per wireless client in this architecture.

  145. 145. Router Cypress-R3 shows the route '172.22.0.0/16 is variably subnetted, 4 subnets, 3 masks' followed by child entries. What does this heading convey?

    • A. The routing table contains multiple subnets of 172.22.0.0 with different prefix lengths, reflecting VLSM in the network design
    • B. The router compressed four routes into one entry to conserve memory
    • C. The network 172.22.0.0 is unstable and has changed masks three times
    • D. Four routing protocols contributed one route each for this network
    Show answer & explanation

    Answer: A
    That heading is how the routing table groups child routes of one classful network when their prefix lengths differ, which is the natural result of variable-length subnet masking. It is a display grouping rather than a compression mechanism, the count refers to subnets rather than contributing protocols, and mask variety indicates design flexibility rather than instability.

  146. 146. A retail chain runs controller-based Wi-Fi at headquarters, but each small store has only two APs and a WAN link that sometimes fails. Which AP mode keeps store clients working during WAN outages while still using central management when the link is up?

    • A. FlexConnect mode, which locally switches traffic and keeps serving clients when the controller is unreachable
    • B. Sniffer mode, which captures frames for later analysis at headquarters
    • C. Rogue detector mode, which validates store APs against a local list
    • D. Monitor mode, which dedicates the AP to scanning during outages
    Show answer & explanation

    Answer: A
    FlexConnect lets a remote AP switch client traffic locally onto the store LAN and continue authenticating clients when the controller across the WAN is unreachable, resuming central control when the link returns. Monitor mode stops serving clients entirely, sniffer mode streams captures to an analyzer rather than serving users, and rogue detector mode watches for unauthorized devices instead of carrying traffic.

  147. 147. A wireless engineer needs to feed raw 802.11 frames from the air into a protocol analyzer running on a desktop to troubleshoot a client roaming problem. Which AP mode supports this task?

    • A. Bridge mode, which relays frames between two wired segments
    • B. Local mode, which serves clients while logging summary statistics
    • C. FlexConnect mode, which caches frames locally during WAN failures
    • D. Sniffer mode, which captures channel traffic and forwards it to a specified analyzer address
    Show answer & explanation

    Answer: D
    In sniffer mode the AP stops serving clients and instead captures every frame on its assigned channel, streaming them to an analyzer host for decoding. Local mode is the standard client-serving mode with only summary visibility, bridge mode joins wired networks over a wireless hop, and FlexConnect concerns local switching rather than packet capture.

  148. 148. The Wi-Fi design for Kestrel Stadium dedicates several APs exclusively to scanning all channels for interference and unauthorized devices; they never serve clients. Which mode are these APs using?

    • A. Workgroup bridge mode
    • B. FlexConnect mode
    • C. Local mode
    • D. Monitor mode
    Show answer & explanation

    Answer: D
    Monitor mode devotes the AP's radios full time to scanning every channel for rogues, intrusion signatures, and interference without accepting client associations. Local mode splits time between serving clients and brief off-channel scans, FlexConnect is about remote-site local switching, and a workgroup bridge associates to another AP on behalf of wired devices.

  149. 149. A facilities team must network several wired ticket printers in a kiosk 90 meters from the nearest wiring closet, with no conduit available. The stadium already has pervasive Wi-Fi. Which wireless solution connects these wired-only devices?

    • A. Create a second SSID reserved for devices without radios
    • B. Set the nearest AP to sniffer mode and plug the printers into it
    • C. Enable FlexConnect on the kiosk printers' built-in interfaces
    • D. Configure an AP as a workgroup bridge that associates to the WLAN on behalf of the wired printers
    Show answer & explanation

    Answer: D
    A workgroup bridge is an AP acting as a wireless client: wired devices plug into it, and it associates to the existing WLAN, extending connectivity where cable cannot reach. Sniffer mode is a capture function that serves no clients, FlexConnect is an AP mode rather than a printer feature, and an SSID cannot help hardware that has no radio at all.

  150. 150. During WLAN setup on a wireless LAN controller, an engineer maps a new SSID to a specific VLAN so that guest traffic exits the controller tagged for the guest network. Which controller construct makes this SSID-to-VLAN mapping?

    • A. A mobility group shared between neighboring controllers
    • B. A WLAN profile bound to a dynamic interface on the controller
    • C. An RF profile assigned to the AP group for that building
    • D. The virtual interface used for client DHCP relay
    Show answer & explanation

    Answer: B
    On a controller, each WLAN profile defines the SSID and its security, and binding it to a dynamic interface determines which VLAN and subnet its client traffic uses when leaving the controller. Mobility groups coordinate roaming between controllers, RF profiles tune radio settings like power and channels, and the virtual interface supports functions like DHCP relay and web authentication rather than VLAN mapping.

  151. 151. A client associating to the SSID 'Voyager-Corp' authenticates successfully, then receives an IP address, and its traffic appears on VLAN 220 at the core. The AP operates in local mode with a centralized controller. Where does the client's traffic enter the wired network?

    • A. At the controller, because local mode tunnels all client data through CAPWAP to the controller before it is switched onto VLAN 220
    • B. At the AP's access switch port, which must carry VLAN 220 as its access VLAN
    • C. Directly at the client, because 802.11 frames already carry VLAN tags
    • D. At the nearest Layer 3 boundary between the AP and the controller
    Show answer & explanation

    Answer: A
    With local mode, client data rides the CAPWAP tunnel from AP to controller and is placed onto the wired VLAN at the controller's interfaces, so VLAN 220 need not exist at the AP's edge switch. The AP's switch port carries only tunnel traffic in its own VLAN, intermediate Layer 3 hops simply route the tunnel packets, and 802.11 frames do not carry 802.1Q VLAN tags themselves.

  152. 152. Router Glacier-R1 holds these routes: 10.16.0.0/12 learned from EIGRP, 10.16.32.0/19 learned from OSPF, and 10.16.32.128/25 configured statically. A packet arrives destined for 10.16.32.200. Which route forwards it?

    • A. The static route to 10.16.32.128/25, because the longest prefix match always wins
    • B. The OSPF route, because dynamic routes outrank static entries
    • C. The EIGRP route, because its administrative distance of 90 is the lowest
    • D. The packet is dropped because three overlapping routes create ambiguity
    Show answer & explanation

    Answer: A
    Forwarding compares the destination against every route and selects the most specific match; 10.16.32.200 falls inside 10.16.32.128/25, whose 25-bit prefix beats the /19 and /12. Administrative distance only breaks ties between sources offering the identical prefix, dynamic routes never outrank statics in forwarding decisions, and overlapping routes are normal rather than ambiguous.

  153. 153. Router Delta-R4 learns the exact prefix 192.168.88.0/24 from both OSPF and an external BGP peer. Which route enters the routing table and why?

    • A. The route with the lower metric installs regardless of protocol
    • B. The eBGP route, because its administrative distance of 20 beats OSPF's 110
    • C. Both routes install and traffic is balanced across them equally
    • D. The OSPF route, because interior protocols are always preferred over exterior ones
    Show answer & explanation

    Answer: B
    When two sources offer the same prefix and length, administrative distance decides: external BGP carries 20 while OSPF carries 110, so the BGP path is installed. There is no rule preferring interior protocols, routes from different protocols are never load-balanced together, and metrics cannot be compared across protocols because each computes them differently.

  154. 154. The output of 'show ip route' on router Fern-R2 includes the line 'O 172.30.8.0/22 [110/74] via 10.1.1.9, 00:12:44, GigabitEthernet0/1'. What do the numbers 110 and 74 represent?

    • A. 110 is the route's cost and 74 is its hop count from the router
    • B. 110 is the process ID and 74 is the area in which the route originated
    • C. 110 is the administrative distance of OSPF and 74 is the route's metric
    • D. 110 is the VLAN of the next hop and 74 is the interface index
    Show answer & explanation

    Answer: C
    Routing table entries show the bracketed pair as administrative distance followed by metric, so 110 identifies the OSPF trust value and 74 is the OSPF cost to reach the prefix. Hop counts belong to distance-vector protocols like RIP, process and area numbers never appear inside the brackets, and neither value has anything to do with VLANs or interface indexes.

  155. 155. A packet arrives at router Onyx-R7 destined for 198.51.77.40, and the routing table holds no matching route and no default route. What does Onyx-R7 do?

    • A. Forwards the packet back to the device it came from for rerouting
    • B. Floods the packet out all interfaces hoping a neighbor has a route
    • C. Buffers the packet until a routing protocol learns a matching prefix
    • D. Drops the packet and may send an ICMP destination unreachable message to the source
    Show answer & explanation

    Answer: D
    Routing is drop-by-default: with no matching prefix and no gateway of last resort, the packet is discarded and the router can notify the sender through ICMP. Routers never flood unroutable packets since that defeats routing entirely, they do not queue packets awaiting future routes, and returning a packet to its previous hop would create a loop rather than a solution.

  156. 156. An engineer inspecting router Basalt-R9 sees 'S* 0.0.0.0/0 [1/0] via 198.51.100.1' in the routing table. What does this entry provide?

    • A. A host route to the single address 198.51.100.1
    • B. A blackhole route that discards all traffic without notification
    • C. A static default route serving as the gateway of last resort for unmatched destinations
    • D. A dynamically learned backbone route to the provider network
    Show answer & explanation

    Answer: C
    The S marks a static route, the asterisk flags it as the gateway of last resort candidate, and the all-zeros prefix matches any destination lacking a more specific route, forwarding it to 198.51.100.1. Dynamic routes carry protocol codes like O or D, discarding requires a null interface target rather than a next-hop address, and a host route would show a /32 prefix for one address.

  157. 157. Router Tundra-R2 receives a packet whose destination matches both a /28 route with administrative distance 110 and a /24 route with administrative distance 1. A colleague argues the /24 wins because static routes are more trusted. How should the engineer respond?

    • A. The colleague is right; administrative distance is always evaluated first
    • B. The router alternates between the two routes since the criteria conflict
    • C. Prefix length is compared before administrative distance, so the /28 forwards the packet despite its higher distance value
    • D. Neither route is used until their administrative distances are made equal
    Show answer & explanation

    Answer: C
    Administrative distance decides which of several sources gets to install a given prefix; once routes are in the table, forwarding uses only longest-prefix match, so the /28 always carries this traffic. Distance never overrides specificity at forwarding time, routers do not alternate between mismatched prefixes, and there is no requirement for distances to match across different prefixes.

  158. 158. A troubleshooter runs 'show ip route 10.90.4.17' on router Quill-R5 and the output names a specific route entry with its outgoing interface and next hop. What did this command do?

    • A. Displayed the single best route the router would use to reach that exact destination address
    • B. Displayed every route the router has ever learned for that network
    • C. Created a temporary host route for that address for testing purposes
    • D. Sent a probe packet to the address and recorded the path taken
    Show answer & explanation

    Answer: A
    Supplying an address to the route display performs a lookup and prints the specific entry that would forward traffic to that destination, including next hop and interface, which is ideal for verifying path selection. Nothing is created or modified, no packets are transmitted the way ping or traceroute would, and the command shows the current best match rather than any historical learning.

  159. 159. Router Sable-R1 has a directly connected interface in 192.168.41.0/24 and also learns 192.168.41.0/24 from a routing protocol on another interface. Which route does the router use for hosts on that network?

    • A. The connected route, because its administrative distance of 0 beats every learned source
    • B. Both routes, splitting traffic between the local interface and the remote path
    • C. The protocol route, because learned routes carry fresher information
    • D. Neither, because a connected and learned duplicate forces the prefix out of the table
    Show answer & explanation

    Answer: A
    Directly connected networks install with distance 0, the most trusted value possible, so the connected entry always wins over any advertisement of the same prefix. Freshness is not a selection criterion, connected and learned duplicates are never load-shared, and the conflict resolves cleanly through distance rather than removing the prefix.

  160. 160. On router Marlin-R6, 'show ip route' displays 'L 10.5.5.1/32 is directly connected, GigabitEthernet0/2' just below a C entry for 10.5.5.0/24. What is the L entry?

    • A. A leaked route imported from another VRF on the same device
    • B. A loopback route created automatically for every physical port
    • C. A local route representing the router's own interface address as a /32
    • D. A legacy route retained from a previous configuration revision
    Show answer & explanation

    Answer: C
    Local routes are /32 entries the router installs for each of its own interface addresses so traffic addressed to the router itself is recognized immediately; they accompany the connected network entry. They are unrelated to loopback interfaces, VRF route leaking uses different mechanisms and labeling, and routing tables do not retain superseded configuration remnants.

  161. 161. Traffic from the Kite branch to 172.28.64.0/18 must transit a firewall at 10.9.9.5 rather than following the shorter path advertised by the WAN protocol. Assuming the branch router already learns the /18 dynamically, which mechanism forces the firewall path?

    • A. Increase the bandwidth statement on the firewall-facing interface
    • B. Configure the firewall to advertise a lower hop count for the network
    • C. Clear the routing table so the firewall path is learned first
    • D. Configure a static route for 172.28.64.0/18 via 10.9.9.5, which outranks the dynamic route by administrative distance
    Show answer & explanation

    Answer: D
    A static route for the identical prefix installs with distance 1, displacing the dynamic entry and steering the traffic through the firewall deterministically. Bandwidth tweaks influence some protocol metrics indirectly and unpredictably, hop count belongs to RIP rather than a general solution, and table clears change nothing because installation order is irrelevant to route preference.

  162. 162. An engineer at Corvid Systems types 'ip route 10.120.8.0 255.255.248.0 172.16.99.2' on router Corvid-R1. What exactly has been configured?

    • A. A default route through 172.16.99.2 for all traffic from 10.120.8.0
    • B. A static route sending traffic for 10.120.8.0/21 to next-hop address 172.16.99.2
    • C. A route advertisement telling neighbors that 10.120.8.0 lives at 172.16.99.2
    • D. A NAT rule translating 10.120.8.0 addresses to 172.16.99.2
    Show answer & explanation

    Answer: B
    The command's three parts are destination network, subnet mask, and next hop, so packets matching 10.120.8.0/21 are forwarded toward 172.16.99.2. A default route would use all zeros for network and mask, static routes are local forwarding instructions rather than advertisements unless redistributed, and address translation is configured through entirely different commands.

  163. 163. Router Heron-R2 connects to headquarters through a fiber circuit and to a backup LTE service through a second interface. The engineer configures the primary default route normally and adds 'ip route 0.0.0.0 0.0.0.0 10.200.1.1 250'. What role does the value 250 play?

    • A. It defines the route's metric, making it less attractive but always active
    • B. It sets the route's bandwidth in megabits for load calculation
    • C. It limits the route to 250 concurrent sessions before overflow
    • D. It raises the route's administrative distance so it installs only when the primary default route disappears
    Show answer & explanation

    Answer: D
    Appending a distance value creates a floating static route: at 250 it loses to the primary route's distance of 1 and stays out of the table until the fiber path's route is withdrawn, then installs to carry traffic over LTE. The trailing number is not bandwidth, no session-count semantics exist for static routes, and unlike a metric adjustment, a floating static is completely absent from the table while the primary survives.

  164. 164. The floating static backup route on router Petrel-R1 never takes over when the primary WAN circuit degrades to 90 percent packet loss, though it works during full outages. Why does the backup fail to activate during degradation?

    • A. Floating static routes activate only once per day by design
    • B. Packet loss reverses the administrative distance comparison
    • C. The backup route requires the primary to be manually deleted first
    • D. The primary static route stays installed as long as its interface remains up, and packet loss alone does not remove it
    Show answer & explanation

    Answer: D
    Static routes are withdrawn when their exit interface goes down or their next hop becomes unresolvable, not when quality degrades, so a lossy but up circuit keeps its route and the floating backup stays dormant; pairing the route with reachability tracking solves this. No daily activation limit exists, distance values never invert, and manual deletion is exactly what floating routes are meant to avoid.

  165. 165. A network engineer configures 'ip route 172.18.40.0 255.255.255.0 GigabitEthernet0/3' on router Osprey-R4, naming only the exit interface on this Ethernet link. What drawback should the engineer expect?

    • A. The route cannot install because Ethernet interfaces require a VLAN ID
    • B. The route works only for the first 100 hosts of the destination network
    • C. Traffic will loop between the router and the switch on that interface
    • D. The router must ARP for every destination host in the network, potentially bloating its ARP table and relying on proxy ARP
    Show answer & explanation

    Answer: D
    On multi-access media, an interface-only static route makes the router treat every destination as directly attached, ARPing for each remote host and depending on a downstream device's proxy ARP replies, which scales poorly; adding a next-hop address avoids this. Ethernet static routes need no VLAN parameter, no loop is created by the syntax, and no host-count limitation exists.

  166. 166. Routers Wren-R1 and Wren-R2 sit at opposite ends of a point-to-point link. Wren-R1 has a static route to the LAN behind Wren-R2, yet pings from Wren-R1's LAN to that remote LAN fail while pings from Wren-R1 itself succeed. What is the most likely missing piece?

    • A. Wren-R1's LAN interface must be added to the static route as a source
    • B. The point-to-point link must run a routing protocol for LAN-to-LAN traffic
    • C. Wren-R2 lacks a return route to the LAN behind Wren-R1, so replies cannot come back
    • D. Static routes only carry router-generated traffic, never LAN traffic
    Show answer & explanation

    Answer: C
    Routing must work in both directions: Wren-R1 sends the pings fine, but Wren-R2 has no route back to the originating LAN, so replies die there; router-sourced pings succeeded because they came from the link address Wren-R2 knows as connected. Static routes carry any transit traffic, dynamic protocols are optional rather than required, and static routes have no source parameter.

  167. 167. A data center team wants traffic destined for the decommissioned block 10.66.0.0/16 silently discarded at router Falcon-R8 instead of following the default route toward the firewall. Which configuration achieves this?

    • A. An outbound access list on every interface denying the block
    • B. Removal of the default route so the traffic has nowhere to go
    • C. A route to 10.66.0.0/16 with a next hop of the router's own address
    • D. A static route for 10.66.0.0/16 pointing to the Null0 interface
    Show answer & explanation

    Answer: D
    Routing the prefix to the null interface discards matching packets efficiently in hardware, overriding the default route through longest-prefix matching, which is the standard blackhole technique. Interface ACLs achieve filtering but burden every edge and miss future interfaces, self-addressed next hops create loops or process-level churn, and deleting the default route breaks all other traffic to serve one goal.

  168. 168. Branch router Lark-R1 needs IPv6 reachability to the corporate prefix 2001:db8:44::/48 through next hop 2001:db8:ff::1. Which statement about configuring this static route is accurate?

    • A. Static routing is unavailable in IPv6 because neighbor discovery replaces it
    • B. IPv6 static routes require an exit interface and cannot use next-hop addresses
    • C. IPv6 routes are configured identically to IPv4 using the ip route command
    • D. The command uses the ipv6 route form, and IPv6 routing must be enabled on the router for forwarding to occur
    Show answer & explanation

    Answer: D
    IPv6 static routes use their own command family, and the router forwards IPv6 only after unicast routing for the protocol is enabled globally. The IPv4 command cannot accept IPv6 prefixes, next-hop global or link-local addresses are fully supported (a link-local next hop additionally names the interface), and static routing is just as fundamental in IPv6 as in IPv4.

  169. 169. Routers Alder-R1 and Alder-R2 share an Ethernet segment. Alder-R1 uses hello and dead timers of 10 and 40 seconds, but a contractor set Alder-R2's hello timer to 5 seconds. What is the effect on their OSPF relationship?

    • A. Alder-R2 wins the DR election because it hellos more frequently
    • B. They become neighbors but the adjacency flaps every 40 seconds
    • C. They never become neighbors because hello and dead intervals must match on the segment
    • D. They form a neighbor relationship using the faster of the two timers
    Show answer & explanation

    Answer: C
    OSPF hello packets carry the timers, and receivers reject hellos whose intervals differ from their own on that network type, so the adjacency never forms and each router logs mismatch errors. There is no negotiation to a common timer, no adjacency exists to flap, and DR elections consider priority and router ID rather than hello frequency.

  170. 170. An engineer defines a static route on router Teal-R3 with next hop 192.0.2.77, an address that is not in any connected subnet and is itself only reachable through another route. What is this arrangement called and what does the router do with it?

    • A. A recursive static route; the router performs an additional lookup to resolve the next hop's own route
    • B. A summarized route; the router advertises both prefixes as one
    • C. A tunneled route; the router encapsulates traffic to reach the next hop
    • D. An invalid route; routers reject next hops outside connected networks
    Show answer & explanation

    Answer: A
    A next hop beyond the connected subnets makes the route recursive: the router looks up the destination, finds 192.0.2.77, then looks up how to reach 192.0.2.77 itself, resolving down to an exit interface. Such routes are accepted as long as the next hop resolves, no encapsulation is implied, and summarization is an entirely separate concept about combining prefixes.

  171. 171. At Meridian Retail, the WAN engineer configures identical static routes to 10.44.0.0/16 through two different upstream next hops, both with default administrative distance. What forwarding behavior results?

    • A. The routes alternate in the table every aging interval
    • B. The second route overwrites the first because duplicates are not allowed
    • C. Only the numerically lower next hop installs; the other is rejected
    • D. Both routes install and the router load-shares traffic to that network across the two next hops
    Show answer & explanation

    Answer: D
    Two static routes to one prefix with equal distance both enter the table, giving equal-cost load sharing and instant failover if one next hop's interface fails. Next-hop numeric values play no role in selection, static routes have no aging mechanism, and identical prefixes through different next hops are separate valid entries rather than duplicates.

  172. 172. A junior engineer asks when a network team should favor static routing over a dynamic protocol for a site. Which scenario is the strongest fit for static routes?

    • A. A service provider backbone carrying full internet routing tables
    • B. A large mesh of data centers where links fail and recover frequently
    • C. Any network in which routers come from more than one vendor
    • D. A stub site with one uplink and a handful of stable prefixes where simplicity and predictability matter most
    Show answer & explanation

    Answer: D
    Static routing shines where topology is tiny and stable: a single-homed stub needs only a default route out and one route in, gaining predictability with zero protocol overhead. Meshes with frequent failures demand automatic reconvergence, provider backbones require dynamic scale far beyond manual entry, and multi-vendor environments simply call for standard protocols rather than statics.

  173. 173. Router Dove-R2's static route to 172.29.128.0/17 uses next hop 10.31.7.2 on interface Gi0/1. That interface goes down at 02:14. What happens to the static route?

    • A. It remains installed but forwards traffic through the router's other interfaces
    • B. It is removed from the routing table because its next hop is no longer reachable through any connected interface
    • C. It stays in the table permanently because static routes never change state
    • D. It converts automatically into a floating route with higher distance
    Show answer & explanation

    Answer: B
    A static route lives in the table only while its next hop resolves; when the sole interface toward 10.31.7.2 fails, resolution breaks and the route is withdrawn until the interface recovers. The router will not silently substitute other interfaces unless a different route resolves the next hop, no automatic distance change occurs, and static routes definitely track interface state despite being manually configured.

  174. 174. The operations team at Skylark Media documents that their branch default route is 'ip route 0.0.0.0 0.0.0.0 203.0.113.9' and asks what traffic this entry matches. What is the correct answer?

    • A. Only traffic destined for public internet addresses
    • B. Broadcast traffic that the router would otherwise discard
    • C. Every destination that fails to match a more specific route in the table
    • D. Only traffic sourced from the 203.0.113.0 network
    Show answer & explanation

    Answer: C
    The all-zeros network and mask match every possible destination, but longest-prefix logic means it is consulted last, catching only traffic with no better route; that is what makes it the default. Matching is not limited to public space since internal unmatched destinations use it too, source addresses never influence destination lookup, and routers do not forward broadcast traffic through unicast routes.

  175. 175. An engineer enables OSPF on router Juniper-R3, which has loopback addresses 10.0.0.9 and 172.16.0.4 plus physical interface addresses 192.168.1.1 and 10.255.255.1, with no router-id command configured. Which router ID does OSPF select?

    • A. 172.16.0.4, the highest IP address among the loopback interfaces
    • B. 10.0.0.9, the lowest loopback address for stability
    • C. 192.168.1.1, the highest address across all interfaces
    • D. 10.255.255.1, the address of the first interface that came up
    Show answer & explanation

    Answer: A
    Router ID selection prefers an explicitly configured value first, then the highest loopback address, then the highest physical interface address; with loopbacks present, 172.16.0.4 beats 10.0.0.9 and the physical addresses never enter the comparison. Highest overall address applies only when no loopbacks exist, lowest is not the rule, and boot order plays no part.

  176. 176. On the Ethernet segment shared by four OSPF routers, Cedar-R2 has priority 0, Cedar-R1 has priority 1, and Cedar-R3 and Cedar-R4 both have priority 100 with router IDs 3.3.3.3 and 4.4.4.4 respectively. Which router becomes the designated router?

    • A. Cedar-R2, because priority 0 marks the most trusted router
    • B. Cedar-R4, because at tied priority the higher router ID wins the DR election
    • C. Cedar-R1, because the lowest nonzero priority takes the role
    • D. Cedar-R3, because lower router IDs are preferred for stability
    Show answer & explanation

    Answer: B
    The DR election chooses the highest priority, breaking ties with the highest router ID, so 4.4.4.4 defeats 3.3.3.3 at their shared priority of 100. Lower router IDs lose rather than win, priority 0 means a router refuses DR candidacy entirely, and low nonzero priorities simply lose to higher ones.

  177. 177. The command 'show ip ospf neighbor' on router Rowan-R5 lists a neighbor stuck in the EXSTART state for twenty minutes. What is the classic cause of this symptom?

    • A. An MTU mismatch between the two routers' interfaces prevents database exchange from starting
    • B. One router has reached its LSA limit and paused flooding
    • C. The routers are in different areas and cannot synchronize
    • D. The neighbor's hello interval is shorter than Rowan-R5's dead interval
    Show answer & explanation

    Answer: A
    EXSTART is where routers negotiate database exchange, and mismatched interface MTUs make one router reject the other's database description packets, freezing the adjacency at this exact state until MTUs agree or checking is disabled. Timer problems block adjacency far earlier at the hello stage, area mismatches also prevent hello acceptance, and LSA limits produce different symptoms entirely.

  178. 178. Router Sequoia-R1 shows a neighbor in the 2WAY state on a multi-access segment and never progresses to FULL. The segment has five routers and adjacencies to two of them show FULL. Is this a problem?

    • A. No; 2WAY indicates the neighbor is in a different area, which is expected
    • B. Yes; 2WAY means authentication failed midway through the exchange
    • C. No; non-DR routers form full adjacencies only with the DR and BDR, remaining in 2WAY with other DROTHER routers
    • D. Yes; every OSPF router must reach FULL with every neighbor on the segment
    Show answer & explanation

    Answer: C
    On broadcast networks OSPF economizes by having all routers fully synchronize only with the designated and backup designated routers; pairs of DROTHER routers deliberately remain in 2WAY, so this display is healthy. Full adjacency between every pair happens only on point-to-point links, authentication failures block state progress before 2WAY, and inter-area neighbors would not appear at all.

  179. 179. An engineer wants OSPF on router Laurel-R2 to advertise the subnet on interface Gi0/2 while never sending hello packets out that interface, because only servers live there. Which feature accomplishes this?

    • A. Configuring the interface as passive under the OSPF process
    • B. Applying an inbound access list blocking protocol 89
    • C. Setting the interface's OSPF priority to zero
    • D. Removing the network statement that covers the interface
    Show answer & explanation

    Answer: A
    A passive interface stays in the OSPF process so its prefix is advertised, but the router suppresses hellos and never forms adjacencies there, exactly right for host-only segments. Priority zero still sends hellos while declining DR duty, filtering protocol 89 breaks things noisily rather than by design, and removing the network statement stops the advertisement the engineer wants to keep.

  180. 180. With a reference bandwidth of 100 Mbps left at default, an engineer notices OSPF assigns the same cost of 1 to both a 1 Gbps and a 10 Gbps interface on router Willow-R7. Why, and what is the fix?

    • A. The interfaces share a duplex setting, which forces equal costs; setting full duplex fixes it
    • B. OSPF measures only latency, not bandwidth; enabling bandwidth measurement fixes it
    • C. The cost formula tops out at gigabit speeds by standard; nothing can change it
    • D. Costs below 1 round up to 1, hiding the difference; raising the reference bandwidth on every OSPF router restores distinction
    Show answer & explanation

    Answer: D
    Cost divides reference bandwidth by interface bandwidth with a minimum of 1, so at the default reference both fast links compute to 1 and path selection cannot tell them apart; raising the reference consistently across the domain restores meaningful costs. Duplex has no role in the formula, OSPF cost derives from configured bandwidth rather than measured latency, and the reference value is fully adjustable.

  181. 181. Routers Fir-R1 and Fir-R2 connect over a point-to-point serial link running OSPF. A new admin asks why 'show ip ospf neighbor' shows the FULL state without any DR or BDR listed. What is the explanation?

    • A. Serial links elect their DR at the area border router instead
    • B. The display omits DR information unless debugging is enabled
    • C. Point-to-point network types skip the DR and BDR election because only two routers exist on the link
    • D. The election failed and OSPF fell back to a direct adjacency
    Show answer & explanation

    Answer: C
    DR and BDR exist to reduce flooding on multi-access segments with many routers; a point-to-point link has exactly two speakers, so the election is skipped and the neighbors simply become fully adjacent. No remote election occurs elsewhere on behalf of the link, the absence is by design rather than failure, and neighbor output always shows DR state where one exists.

  182. 182. A network at Halberd Insurance runs single-area OSPFv2. The engineer types 'network 10.24.16.0 0.0.15.255 area 0' under the OSPF process on router Hal-R1. What does this statement actually control?

    • A. The range of addresses OSPF may assign to new adjacencies
    • B. Which remote prefixes the router will accept into its routing table
    • C. The summary advertisement the router sends to other areas
    • D. Which interfaces join OSPF in area 0, namely any whose address falls within 10.24.16.0 through 10.24.31.255
    Show answer & explanation

    Answer: D
    The network statement matches interface addresses using the wildcard, enrolling matching interfaces into the process and area; their connected prefixes are then advertised. It filters nothing inbound, OSPF never assigns addresses to anything, and summarization between areas is configured with a different command on area border routers.

  183. 183. After a topology change, all routers in area 0 at Garnet Logistics run the same computation to rebuild their routing tables from the link-state database. Which algorithm are they executing, and what does each router compute?

    • A. The Bellman-Ford algorithm, computing hop counts to each neighbor
    • B. The shortest path first algorithm, computing a tree of least-cost paths from itself to every destination
    • C. A spanning tree algorithm, electing a root router for the area
    • D. The diffusing update algorithm, computing feasible successors for each route
    Show answer & explanation

    Answer: B
    Every OSPF router runs Dijkstra's shortest path first over the shared database, rooting the tree at itself and deriving least-cost paths to all networks. Diffusing updates and feasible successors belong to EIGRP, Bellman-Ford with hop counts describes RIP, and spanning tree with root elections is a Layer 2 protocol concept absent from OSPF.

  184. 184. An engineer needs OSPF authentication on the link between routers Aspen-Edge and Aspen-Core to prevent a rogue device from forming an adjacency. Which statement about enabling authentication is true?

    • A. Only the DR needs the key because it relays all adjacency requests
    • B. Both ends of the link must use the same authentication type and key, or the adjacency will not form
    • C. Enabling authentication forces the network type to point-to-point
    • D. Authentication is negotiated automatically once either side enables it
    Show answer & explanation

    Answer: B
    Authentication parameters are validated on every OSPF packet, so a type or key mismatch causes each router to discard the other's hellos and the neighbor relationship dies immediately; both ends must agree exactly. The DR has no authentication proxy role, there is no negotiation of keys or types, and network type is configured independently of authentication.

  185. 185. Router Tamarack-R4's OSPF adjacency to a neighbor repeatedly cycles between FULL and DOWN roughly every 40 seconds, and pings across the link show intermittent loss. The timers match on both ends. What is the most probable cause?

    • A. An unstable link is dropping hellos long enough for the dead timer to expire, tearing down and rebuilding the adjacency
    • B. OSPF areas renumber automatically during instability
    • C. The neighbor's router ID changes on every hello, forcing resets
    • D. A duplicate router ID exists elsewhere in a different area, which is harmless
    Show answer & explanation

    Answer: A
    Losing hellos for a full dead interval, 40 seconds on broadcast networks by default, kills the adjacency, and its rebuild followed by more loss produces exactly this flapping rhythm; the ping loss corroborates a lossy link. Router IDs never change per hello, areas are static configuration, and while duplicate IDs cause real problems, they do not produce this timed flap and the distractor even mislabels them harmless.

  186. 186. A review of router Basil-R2's configuration shows 'ip ospf 10 area 0' entered directly on interface Gi0/1 rather than a network statement under the routing process. What does this configuration do?

    • A. It advertises a tenth of the interface's bandwidth into area 0
    • B. It limits the interface to ten adjacencies in area 0
    • C. It enables OSPF process 10 on that specific interface and places it in area 0, an alternative to network statements
    • D. It is invalid because OSPF can only be enabled under the process
    Show answer & explanation

    Answer: C
    Interface-mode OSPF enablement binds the interface to the named process and area directly, a per-interface alternative many teams prefer for clarity over wildcard-based network statements. The 10 identifies the process rather than an adjacency count, bandwidth advertising fractions do not exist, and the syntax is fully valid on modern software.

  187. 187. Two OSPF routers on the Foxglove LAN segment have formed a FULL adjacency. Router Fox-R1 then receives a new LSA from a downstream neighbor. What does Fox-R1 do with it?

    • A. Installs it in its link-state database and floods it to other neighbors so all routers converge on identical databases
    • B. Converts it into a distance-vector update before propagating it
    • C. Forwards it only to the router that originated the network's routing table
    • D. Holds it until the next scheduled thirty-minute database refresh
    Show answer & explanation

    Answer: A
    Link-state operation depends on reliable flooding: a newly received LSA is acknowledged, stored, and re-flooded out other OSPF interfaces so every router in the area maintains the same database before running its own SPF calculation. There is no single routing table owner in OSPF, no conversion to distance-vector formats, and flooding is immediate rather than deferred to periodic refresh cycles.

  188. 188. The command 'show ip ospf interface Gi0/0' on router Nettle-R6 reports 'State DROTHER, Priority 0'. What do these values reveal about this router on the attached segment?

    • A. It is the designated router but is advertising modestly
    • B. It has been elected as the segment's backup designated router
    • C. Its adjacencies are administratively suspended pending priority change
    • D. It cannot become the DR or BDR because its priority is zero, so it remains an ordinary router on the segment
    Show answer & explanation

    Answer: D
    Priority 0 withdraws a router from DR and BDR candidacy entirely, so it operates as a DROTHER, forming full adjacencies with the elected DR and BDR while never standing for election itself. Backup designated status would display differently, adjacencies remain fully operational rather than suspended, and DROTHER by definition means not the designated router.

  189. 189. Routers Yarrow-R1 and Yarrow-R2 have matching timers and areas but fail to form an OSPF adjacency across a LAN. Yarrow-R1's interface is 10.8.4.1/24 while Yarrow-R2's was fat-fingered as 10.8.5.2/24. Why does the adjacency fail?

    • A. The mismatched addresses trigger a duplicate router ID condition
    • B. The interfaces are in different subnets, and OSPF requires neighbors on a broadcast segment to share one subnet
    • C. OSPF cannot run between addresses whose third octets differ by exactly one
    • D. Adjacency requires the lower address to initiate, which failed here
    Show answer & explanation

    Answer: B
    Hello validation on broadcast networks includes checking that the neighbor's address and mask place it in the same subnet; 10.8.4.1/24 and 10.8.5.2/24 fall in different /24 blocks, so each router ignores the other's hellos. Octet arithmetic beyond subnet membership is meaningless, router IDs are unrelated to interface subnet placement, and no initiation ordering rule based on address values exists.

  190. 190. An engineer runs 'show ip protocols' on router Clover-R3 and sees OSPF process 7 with router ID 172.16.255.1 and two network statements. Later the engineer adds a loopback with a higher address, but the router ID remains 172.16.255.1 even after saving. Why?

    • A. The new loopback must first be advertised into OSPF before it is eligible
    • B. The router ID is chosen when the process starts and is retained until the process restarts or is cleared
    • C. Router IDs can only change during a maintenance window flag set on the process
    • D. Saved configurations lock the router ID permanently on the platform
    Show answer & explanation

    Answer: B
    OSPF selects its router ID once at process initialization and deliberately keeps it stable; new candidate addresses are considered only when the process restarts or the ID is cleared, because changing the ID forces all adjacencies to rebuild. No maintenance-window mechanism exists, saving configuration does not freeze identifiers, and advertisement of the loopback is irrelevant to ID candidacy.

  191. 191. At Ironbark Freight, the OSPF design keeps every router and every interface in area 0. A director asks what limits this single-area design has as the network grows to hundreds of routers. What is the accurate answer?

    • A. Every topology change triggers SPF recalculation on all routers and the shared database grows large, increasing CPU and memory load
    • B. Routers in one area cannot summarize their own connected routes to each other
    • C. Area 0 cannot contain redundant links, limiting resilience
    • D. Single-area OSPF stops forming adjacencies after fifty routers by specification
    Show answer & explanation

    Answer: A
    In one area every router holds the full topology, so each flap floods domain-wide and forces SPF runs everywhere, which is exactly why multi-area hierarchies exist for large networks. No fifty-router protocol ceiling exists, area 0 handles arbitrary redundancy, and intra-area routers exchange full link-state detail by design rather than as a defect of summarization.

  192. 192. Router Primrose-R1 must advertise its default route into OSPF so branch routers learn their exit path. The engineer adds 'default-information originate' under the process. Under what condition will Primrose-R1 advertise the default?

    • A. Only if the router is elected DR on at least one segment
    • B. Immediately and unconditionally, because the command forces advertisement
    • C. Only while Primrose-R1 itself has a default route in its routing table, unless the always keyword is added
    • D. Only after every neighbor reaches the FULL state on all interfaces
    Show answer & explanation

    Answer: C
    The plain form of the command advertises a default into the domain only when the originating router actually possesses one, protecting the network from advertising a black hole; appending always removes that dependency. The base command is therefore conditional rather than unconditional, neighbor states gate nothing about origination, and DR status is completely unrelated to default advertisement.

  193. 193. A capture on the Mulberry LAN shows OSPF packets addressed to 224.0.0.5 and others to 224.0.0.6. Which routers process each address?

    • A. Both addresses reach all routers; the second is a retransmission channel
    • B. All OSPF routers listen to 224.0.0.5, while 224.0.0.6 is processed by the DR and BDR
    • C. 224.0.0.5 reaches only the DR, and 224.0.0.6 reaches all routers
    • D. 224.0.0.5 is used in area 0 and 224.0.0.6 in all other areas
    Show answer & explanation

    Answer: B
    OSPF reserves the all-SPF-routers group 224.0.0.5 for messages every router must hear, such as hellos, and the all-DR-routers group 224.0.0.6 for updates that DROTHER routers send up to the designated and backup designated routers. The roles are the reverse of the second option, no retransmission channel exists in that form, and the groups have nothing to do with area numbering.

  194. 194. A log review at Whimbrel Data shows a message tagged with severity 0 arriving overnight. How should the on-call engineer interpret this severity?

    • A. As a warning about elevated interface utilization
    • B. As an informational notice about a routine configuration save
    • C. As an emergency indicating the system is unusable, the most severe syslog level defined
    • D. As a debug message produced by a technician's troubleshooting session
    Show answer & explanation

    Answer: C
    Syslog severities run from 0 through 7 with 0 as emergencies, reserved for a system rendered unusable, demanding immediate response. Debug output sits at the opposite end at 7, informational messages at 6, and warnings at 4, so none of those interpretations match a severity 0 event.

  195. 195. Hosts on the 10.50.20.0/24 LAN at Copperfield Labs use gateway 10.50.20.1, which is a virtual address answered by whichever of routers Cop-R1 and Cop-R2 is active under HSRP. Cop-R1 fails at noon. What do the hosts experience?

    • A. Nothing at all, because hosts always maintain sessions to both routers simultaneously
    • B. A brief interruption at most, because Cop-R2 takes over the virtual IP and virtual MAC without any host reconfiguration
    • C. A full outage until each host times out its ARP cache and rediscovers a gateway
    • D. A permanent outage until DHCP renews the hosts' leases with the new gateway
    Show answer & explanation

    Answer: B
    First-hop redundancy works because the virtual IP and its virtual MAC are shared state: when the active router dies, the standby assumes both, so host ARP entries remain valid and forwarding resumes within the failover interval. Hosts never need to re-ARP or renew leases, and hosts hold no parallel gateway sessions; the failover is fast but not literally seamless in every case.

  196. 196. A capture on VLAN 70 shows periodic packets from 10.7.0.2 and 10.7.0.3 to multicast 224.0.0.102 with a destination MAC of 0000.0c9f.f046. The gateway address 10.7.0.1 resolves to that same virtual MAC style. Which protocol is running?

    • A. GLBP, identifiable by its per-host round-robin of physical MACs
    • B. HSRP version 2, which uses multicast 224.0.0.102 and virtual MACs in the 0000.0c9f.fxxx range
    • C. VRRP, which always uses MAC addresses beginning 0000.5e00.01
    • D. Proxy ARP, since multicast hellos are not used by any FHRP
    Show answer & explanation

    Answer: B
    The multicast group 224.0.0.102 and the 0000.0c9f.fxxx virtual MAC format are signatures of HSRP version 2, whose group number appears in the MAC's final digits. VRRP advertises to 224.0.0.18 with its distinct 0000.5e00.01xx MAC family, GLBP hands out multiple virtual MACs from a different range, and proxy ARP is a router ARP behavior with no hello packets at all.

  197. 197. Routers Nickel-R1 (priority 110) and Nickel-R2 (priority 100) run HSRP for VLAN 15. Nickel-R1 reboots for maintenance and, upon returning, never resumes the active role even though its priority is higher. Why?

    • A. Nickel-R2 automatically raised its own priority upon becoming active
    • B. HSRP priorities reset to zero after any reboot and must be reconfigured
    • C. Preemption is disabled by default in HSRP, so the current active router keeps the role regardless of priority
    • D. The virtual address moved permanently to Nickel-R2's physical interface
    Show answer & explanation

    Answer: C
    HSRP holds elections only when the active router disappears; without preemption enabled, a returning higher-priority router waits indefinitely, which is why designs that want deterministic placement configure preempt. Priorities persist in configuration across reboots, active routers never self-adjust priority, and the virtual address is shared protocol state rather than something permanently bound to a physical interface.

  198. 198. An architect compares first-hop redundancy options for a customer that insists on an open standard supported by several router vendors. Which protocol satisfies the requirement, and what is one behavioral difference from Cisco's proprietary option?

    • A. GLBP, which is standards-based and disables preemption entirely
    • B. VRRP, which is standards-based and enables preemption by default unlike HSRP
    • C. LACP, which provides gateway redundancy across vendors
    • D. HSRP, which became an open standard in its second version
    Show answer & explanation

    Answer: B
    VRRP is the standards-track first-hop redundancy protocol implemented across vendors, and its master election preempts by default, the opposite of HSRP's conservative default. GLBP is Cisco proprietary like HSRP, HSRP never became a standard in any version, and LACP aggregates links rather than providing gateway redundancy.

  199. 199. A network automation course at Serin Institute explains why REST APIs are described as stateless. Which statement captures the meaning?

    • A. Clients may only call the API once per authentication lifetime
    • B. The server refuses concurrent requests from multiple clients
    • C. The API forgets all device data after every call, requiring database rebuilds
    • D. Each request carries everything the server needs, and the server retains no client session between requests
    Show answer & explanation

    Answer: D
    Statelessness means no server-side session memory: every call is self-contained with its own credentials and parameters, which is what lets REST services scale horizontally behind load balancers. The device inventory itself persists in whatever store the application uses, call counts are not limited by the principle, and concurrency is a strength of the model rather than a restriction.

  200. 200. A design review at Larkspur Bank notes that with HSRP, the standby router's uplink bandwidth sits idle for VLAN 30's outbound traffic. Which FHRP addresses this concern, and how?

    • A. HSRP version 2, which doubles the virtual MAC space for two active routers
    • B. VRRP, which broadcasts every packet to both routers for parallel forwarding
    • C. No FHRP can use more than one gateway; only routing protocols balance load
    • D. GLBP, which answers ARP requests with different virtual MACs so hosts spread traffic across multiple forwarding gateways
    Show answer & explanation

    Answer: D
    GLBP's virtue is active-active forwarding: the elected gateway hands out up to four virtual MACs in ARP replies, so different hosts forward through different routers while sharing one virtual IP. VRRP never duplicates packets to both routers, HSRP version 2 expands group numbering rather than enabling dual active forwarding for one group, and per-host gateway load sharing is exactly what GLBP exists to do.

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Frequently asked questions

Which CCNA 200-301 domains should I spend the most practice time on?

<p>The official exam topics are organized into 6 content domains, and they are not weighted equally. IP Connectivity is the most heavily weighted domain at 25%, followed by Network Fundamentals at 20% and Network Access at 20% — together those three domains account for 65% of the exam. The remaining weight goes to Security Fundamentals at 15%, IP Services at 10%, and Automation and Programmability at 10%.</p><p>A sensible practice plan mirrors those weights: put the bulk of your question drilling into routing, switching, and fundamentals, but don't skip the smaller domains entirely — a 10% domain can still decide a borderline result.</p>

How long is the CCNA exam, and how should I pace my practice tests?

<p>The CCNA 200-301 is a 120-minute exam. When you sit full-length practice tests, run them against that same two-hour clock so your pacing becomes automatic before exam day.</p><p>Because the time limit is fixed, it pays to practice moving on quickly: if a simulation or long scenario question stalls you, note it, keep going, and bank the easier points first. Timed practice is the only reliable way to find out whether your current speed actually fits inside 120 minutes.</p>

How much does the CCNA exam cost, and why does practicing first matter financially?

<p>The exam fee is 300 USD, paid to Cisco's testing partner Pearson VUE, and it covers a single attempt. That means a failed attempt requires paying the full fee again to retest — so free practice questions are effectively insurance on a 300 USD bet. A reasonable benchmark is to keep drilling until you score consistently well across all six domains before you book a seat.</p><p>Once you pass, the CCNA certification is valid for 3 years, so the preparation effort pays off over a multi-year credential, not just a single test day.</p>

Can I take the CCNA online, or do I have to go to a test center?

<p>Both options exist. The CCNA is delivered through Pearson VUE, Cisco's authorized exam delivery provider. You can sit it in a proctored environment at a Pearson VUE Authorized Test Center, or take it online through the OnVUE online proctored service, where a live proctor monitors you by webcam. Either way, you schedule through the Pearson VUE testing portal by signing in to your Cisco certification account.</p><p>If you choose OnVUE, verify your setup before exam day: Pearson VUE requires a minimum internet speed of 6 Mbps download and 2 Mbps upload. Testing your connection and workspace in advance avoids losing your attempt to a technical failure.</p>

Can I use this bank as a full CCNA mock exam?

Yes. Sit a timed 120-minute block — the length of the real 200-301 exam — and pull questions from all six domains. Mirror Cisco's weighting when you build the set: IP Connectivity is the heaviest domain at 25%, with Network Fundamentals and Network Access at 20% each. Score it, read every explanation you missed, and repeat with fresh questions until timed runs pass with room to spare.